QuestionEvaluate $\left|c^{2}+b^{2}\right|$ for $a=5$ , $b=-3$ , and $c=-2$ .

Studdy Solution

STEP 1

Assumptions1. The value of $a$ is5. The value of $b$ is -33. The value of $c$ is -4. The absolute value of a number is its distance from zero on the number line, regardless of direction. Therefore, the absolute value of a number is always non-negative.

STEP 2

We are asked to evaluate $\left|c^{2}+b^{2}\right|$ . We can do this by first calculating the value of $c^{2}+b^{2}$ .
$c^{2}+b^{2} = (-2)^{2} + (-)^{2}$

STEP 3

Calculate the value of $c^{2}+b^{2}$ .
$c^{2}+b^{2} = (-2)^{2} + (-3)^{2} = +9$

STEP 4

Calculate the sum.
$c^{2}+b^{2} =4 +9 =13$

STEP 5

Now that we have the value of $c^{2}+b^{2}$ , we can find the absolute value.
$\left|c^{2}+b^{2}\right| = |13|$

STEP 6

Calculate the absolute value.
$\left|c^{2}+b^{2}\right| = |13| =13$ So, $\left|c^{2}+b^{2}\right|$ equals13.

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QuestionEvaluate $\left|c^{2}+b^{2}\right|$ for $a=5$ , $b=-3$ , and $c=-2$ .

Studdy Solution

STEP 1

Assumptions1. The value of $a$ is5. The value of $b$ is -33. The value of $c$ is -4. The absolute value of a number is its distance from zero on the number line, regardless of direction. Therefore, the absolute value of a number is always non-negative.

STEP 2

We are asked to evaluate $\left|c^{2}+b^{2}\right|$ . We can do this by first calculating the value of $c^{2}+b^{2}$ .
$c^{2}+b^{2} = (-2)^{2} + (-)^{2}$

STEP 3

Calculate the value of $c^{2}+b^{2}$ .
$c^{2}+b^{2} = (-2)^{2} + (-3)^{2} = +9$

STEP 4

Calculate the sum.
$c^{2}+b^{2} =4 +9 =13$

STEP 5

Now that we have the value of $c^{2}+b^{2}$ , we can find the absolute value.
$\left|c^{2}+b^{2}\right| = |13|$

STEP 6

Calculate the absolute value.
$\left|c^{2}+b^{2}\right| = |13| =13$ So, $\left|c^{2}+b^{2}\right|$ equals13.

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QuestionEvaluate ∣c2+b2∣\left|c^{2}+b^{2}\right|∣∣​c2+b2∣∣​ for a=5a=5a=5, b=−3b=-3b=−3, and c=−2c=-2c=−2.

Studdy Solution

STEP 1

Assumptions1. The value of aaa is5. The value of bbb is -33. The value of ccc is -4. The absolute value of a number is its distance from zero on the number line, regardless of direction. Therefore, the absolute value of a number is always non-negative.

STEP 2

We are asked to evaluate ∣c2+b2∣\left|c^{2}+b^{2}\right|∣∣​c2+b2∣∣​. We can do this by first calculating the value of c2+b2c^{2}+b^{2}c2+b2.c2+b2=(−2)2+(−)2c^{2}+b^{2} = (-2)^{2} + (-)^{2}c2+b2=(−2)2+(−)2

STEP 3

Calculate the value of c2+b2c^{2}+b^{2}c2+b2.c2+b2=(−2)2+(−3)2=+9c^{2}+b^{2} = (-2)^{2} + (-3)^{2} = +9c2+b2=(−2)2+(−3)2=+9

STEP 4

Calculate the sum.c2+b2=4+9=13c^{2}+b^{2} =4 +9 =13c2+b2=4+9=13

STEP 5

Now that we have the value of c2+b2c^{2}+b^{2}c2+b2, we can find the absolute value.∣c2+b2∣=∣13∣\left|c^{2}+b^{2}\right| = |13|∣∣​c2+b2∣∣​=∣13∣

STEP 6

Calculate the absolute value.∣c2+b2∣=∣13∣=13\left|c^{2}+b^{2}\right| = |13| =13∣∣​c2+b2∣∣​=∣13∣=13So, ∣c2+b2∣\left|c^{2}+b^{2}\right|∣∣​c2+b2∣∣​ equals13.

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QuestionEvaluate $\left|c^{2}+b^{2}\right|$ for $a=5$ , $b=-3$ , and $c=-2$ .

Assumptions1. The value of $a$ is5. The value of $b$ is -33. The value of $c$ is -4. The absolute value of a number is its distance from zero on the number line, regardless of direction. Therefore, the absolute value of a number is always non-negative.

We are asked to evaluate $\left|c^{2}+b^{2}\right|$ . We can do this by first calculating the value of $c^{2}+b^{2}$ .
$c^{2}+b^{2} = (-2)^{2} + (-)^{2}$

Calculate the value of $c^{2}+b^{2}$ .
$c^{2}+b^{2} = (-2)^{2} + (-3)^{2} = +9$

Calculate the sum.
$c^{2}+b^{2} =4 +9 =13$

Now that we have the value of $c^{2}+b^{2}$ , we can find the absolute value.
$\left|c^{2}+b^{2}\right| = |13|$

Calculate the absolute value.
$\left|c^{2}+b^{2}\right| = |13| =13$ So, $\left|c^{2}+b^{2}\right|$ equals13.