Math  /  Algebra

QuestionEvalúa x2+2y÷2w+3zx^{2}+2 y \div 2 w+3 z para w=2,x=5,y=8w=2, x=5, y=8 yz=3y z=3

Studdy Solution

STEP 1

1. We are given the expression x2+2y÷2w+3z x^{2} + 2y \div 2w + 3z .
2. The values provided are w=2 w = 2 , x=5 x = 5 , y=8 y = 8 , and z=3 z = 3 .
3. We need to evaluate the expression using these values.

STEP 2

1. Substitute the given values into the expression.
2. Simplify the expression by performing arithmetic operations.

STEP 3

Substitute the given values into the expression:
(5)2+2(8)÷2(2)+3(3) (5)^{2} + 2(8) \div 2(2) + 3(3)

STEP 4

Calculate the square of x x :
52=25 5^{2} = 25

STEP 5

Calculate the product 2y 2y :
2×8=16 2 \times 8 = 16

STEP 6

Divide the result by 2w 2w :
16÷(2×2)=16÷4=4 16 \div (2 \times 2) = 16 \div 4 = 4

STEP 7

Calculate the product 3z 3z :
3×3=9 3 \times 3 = 9

STEP 8

Add the results from the previous steps:
25+4+9=38 25 + 4 + 9 = 38
The evaluated expression is:
38 \boxed{38}

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