Math

QuestionFind the limit as xx approaches infinity for x22x\frac{x^{2}}{2^{x}}. Evaluate f(x)=x22xf(x)=\frac{x^{2}}{2^{x}} for x=0,1,,100x=0,1,\ldots,100.

Studdy Solution

STEP 1

Assumptions1. We are asked to find the limit as x approaches infinity of the function f(x)=xxf(x)=\frac{x^{}}{^{x}}. . We are asked to evaluate the function at x=0,1,,3,4,5,6,7,8,9,10,20,50x=0,1,,3,4,5,6,7,8,9,10,20,50, and100.
3. We are asked to use a graph of the function to support our guess.

STEP 2

Let's start by evaluating the function f(x)=x22xf(x)=\frac{x^{2}}{2^{x}} at the given values of x.

STEP 3

Evaluate the function at x=0x=0.
f(0)=0220=0f(0) = \frac{0^{2}}{2^{0}} =0

STEP 4

Evaluate the function at x=1x=1.
f(1)=1221=0.f(1) = \frac{1^{2}}{2^{1}} =0.

STEP 5

Evaluate the function at x=2x=2.
f(2)=2222=1f(2) = \frac{2^{2}}{2^{2}} =1

STEP 6

Evaluate the function at x=3x=3.
f(3)=3223=1.125f(3) = \frac{3^{2}}{2^{3}} =1.125

STEP 7

Evaluate the function at x=4x=4.
f(4)=4224=1f(4) = \frac{4^{2}}{2^{4}} =1

STEP 8

Evaluate the function at x=5x=5.
f(5)=5225=0.78125f(5) = \frac{5^{2}}{2^{5}} =0.78125

STEP 9

Evaluate the function at x=6x=6.
f(6)=6226=.5625f(6) = \frac{6^{2}}{2^{6}} =.5625

STEP 10

Evaluate the function at x=7x=7.
f(7)=7227=0.3828125f(7) = \frac{7^{2}}{2^{7}} =0.3828125

STEP 11

Evaluate the function at x=8x=8.
f(8)=88=0.25f(8) = \frac{8^{}}{^{8}} =0.25

STEP 12

Evaluate the function at x=9x=9.
f(9)=9229=0.158203125f(9) = \frac{9^{2}}{2^{9}} =0.158203125

STEP 13

Evaluate the function at x=10x=10.
f(10)=102210=0.09765625f(10) = \frac{10^{2}}{2^{10}} =0.09765625

STEP 14

Evaluate the function at x=20x=20.
f(20)=202220=0.00009536743f(20) = \frac{20^{2}}{2^{20}} =0.00009536743

STEP 15

Evaluate the function at x=50x=50.
f(50)=5022500f(50) = \frac{50^{2}}{2^{50}} \approx0

STEP 16

Evaluate the function at x=100x=100.
f(100)=100221000f(100) = \frac{100^{2}}{2^{100}} \approx0

STEP 17

From the values obtained, we can see that as x increases, the value of the function decreases and approaches0.

STEP 18

To further support our guess, we can plot a graph of the function f(x)=x22xf(x)=\frac{x^{2}}{2^{x}}.

STEP 19

From the graph, we can see that as x approaches infinity, the value of the function approaches.

STEP 20

Therefore, we can guess that the limit of the function as x approaches infinity is0.
limxxx=0\lim{x \rightarrow \infty} \frac{x^{}}{^{x}} =0

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