Math  /  Discrete

QuestionEsercizio Siano A={3,4,7,9}A=\{3,4,7,9\} e B={0,2,4,6,8,10,12}B=\{0,2,4,6,8,10,12\} insiemi dentro all'insieme ambiente S={0,1,2,3,4,5,6,7,8,9,10,11,12}S=\{0,1,2,3,4,5,6,7,8,9,10,11,12\}. Lista gli elementi di ciascuno dei seguenti insiemi. Il complemento di AA è denotato AA^{\prime} e il complemento di BB è denotato BB^{\prime}. (a) A=A^{\prime}= \square (b) B=B^{\prime}= \square (c) AB=A \cup B= \square (d) (AB)=\left(A^{\prime} \cap B\right)^{\prime}= \square (e) (BA)=\left(B^{\prime} \cup A\right)^{\prime}= \square

Studdy Solution

STEP 1

1. The universal set is S={0,1,2,3,4,5,6,7,8,9,10,11,12} S = \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12\} .
2. The set A={3,4,7,9} A = \{3, 4, 7, 9\} and the set B={0,2,4,6,8,10,12} B = \{0, 2, 4, 6, 8, 10, 12\} .
3. The complement of a set A A , denoted A A^{\prime} , is the set of elements in S S that are not in A A .

STEP 2

1. Find the complement of set A A .
2. Find the complement of set B B .
3. Find the union of sets A A and B B .
4. Find the complement of the intersection of A A^{\prime} and B B .
5. Find the complement of the union of B B^{\prime} and A A .

STEP 3

To find the complement of A A , list all elements in S S that are not in A A .
A={3,4,7,9} A = \{3, 4, 7, 9\} A=SA={0,1,2,5,6,8,10,11,12} A^{\prime} = S - A = \{0, 1, 2, 5, 6, 8, 10, 11, 12\}

STEP 4

To find the complement of B B , list all elements in S S that are not in B B .
B={0,2,4,6,8,10,12} B = \{0, 2, 4, 6, 8, 10, 12\} B=SB={1,3,5,7,9,11} B^{\prime} = S - B = \{1, 3, 5, 7, 9, 11\}

STEP 5

To find the union of A A and B B , list all elements that are in either A A or B B or both.
AB={3,4,7,9}{0,2,4,6,8,10,12} A \cup B = \{3, 4, 7, 9\} \cup \{0, 2, 4, 6, 8, 10, 12\} AB={0,2,3,4,6,7,8,9,10,12} A \cup B = \{0, 2, 3, 4, 6, 7, 8, 9, 10, 12\}

STEP 6

First, find the intersection of A A^{\prime} and B B , then find the complement of that intersection.
AB={0,1,2,5,6,8,10,11,12}{0,2,4,6,8,10,12} A^{\prime} \cap B = \{0, 1, 2, 5, 6, 8, 10, 11, 12\} \cap \{0, 2, 4, 6, 8, 10, 12\} AB={0,2,6,8,10,12} A^{\prime} \cap B = \{0, 2, 6, 8, 10, 12\}
Now, find the complement:
(AB)=S{0,2,6,8,10,12} \left(A^{\prime} \cap B\right)^{\prime} = S - \{0, 2, 6, 8, 10, 12\} (AB)={1,3,4,5,7,9,11} \left(A^{\prime} \cap B\right)^{\prime} = \{1, 3, 4, 5, 7, 9, 11\}

STEP 7

First, find the union of B B^{\prime} and A A , then find the complement of that union.
BA={1,3,5,7,9,11}{3,4,7,9} B^{\prime} \cup A = \{1, 3, 5, 7, 9, 11\} \cup \{3, 4, 7, 9\} BA={1,3,4,5,7,9,11} B^{\prime} \cup A = \{1, 3, 4, 5, 7, 9, 11\}
Now, find the complement:
(BA)=S{1,3,4,5,7,9,11} \left(B^{\prime} \cup A\right)^{\prime} = S - \{1, 3, 4, 5, 7, 9, 11\} (BA)={0,2,6,8,10,12} \left(B^{\prime} \cup A\right)^{\prime} = \{0, 2, 6, 8, 10, 12\}
The solutions are: (a) A={0,1,2,5,6,8,10,11,12} A^{\prime} = \{0, 1, 2, 5, 6, 8, 10, 11, 12\} (b) B={1,3,5,7,9,11} B^{\prime} = \{1, 3, 5, 7, 9, 11\} (c) AB={0,2,3,4,6,7,8,9,10,12} A \cup B = \{0, 2, 3, 4, 6, 7, 8, 9, 10, 12\} (d) (AB)={1,3,4,5,7,9,11} \left(A^{\prime} \cap B\right)^{\prime} = \{1, 3, 4, 5, 7, 9, 11\} (e) (BA)={0,2,6,8,10,12} \left(B^{\prime} \cup A\right)^{\prime} = \{0, 2, 6, 8, 10, 12\}

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