Math  /  Geometry

QuestionEn la siguiente figura, mMKJ=137m \angle M K J=137^{\circ}. (a) Escribir una ecuación para hallar x. Asegurarse de utilizar un signo de "=" en su respuesta.
Ecuación: \square (b) Resolver para xx. \square x=x=

Studdy Solution

STEP 1

1. The sum of angles around a point is 360 360^\circ .
2. We have three angles: MKJ=137\angle MKJ = 137^\circ, JKL=71\angle JKL = 71^\circ, and LKM=(6x)\angle LKM = (6x)^\circ.

STEP 2

1. Write an equation for the sum of the angles.
2. Solve for x x .

STEP 3

We know the sum of angles around point K K is 360 360^\circ . Therefore, we can write the equation:
MKJ+JKL+LKM=360 \angle MKJ + \angle JKL + \angle LKM = 360^\circ
Substitute the given values into the equation:
137+71+(6x)=360 137^\circ + 71^\circ + (6x)^\circ = 360^\circ
Ecuación: 137+71+6x=360 137 + 71 + 6x = 360

STEP 4

Now, solve the equation for x x .
First, simplify the left side of the equation:
137+71=208 137 + 71 = 208
So the equation becomes:
208+6x=360 208 + 6x = 360

STEP 5

Subtract 208 208 from both sides to isolate the term with x x :
6x=360208 6x = 360 - 208
6x=152 6x = 152

STEP 6

Divide both sides by 6 6 to solve for x x :
x=1526 x = \frac{152}{6}
x=25.3333 x = 25.3333\ldots
Since x x is typically an integer in these types of problems, we can express it as a fraction:
x=763 x = \frac{76}{3}
The solution for x x is:
x=763 x = \frac{76}{3}

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