QuestionEvaluate $E(22)$ for the function $E(x)=\sqrt{4x+33}$ . What is $E(22)$ ?

Studdy Solution

STEP 1

Assumptions1. The function is $(x)=\sqrt{4 x+33}$ . We need to evaluate $(22)$

STEP 2

We can evaluate $(22)$ by substituting $x$ with $22$ in the function.
$(22)=\sqrt{4(22)+33}$

STEP 3

First, calculate the value inside the square root by multiplying $$ with $22$ and then adding $33$.
$(22)=\sqrt{ \times22 +33}$

STEP 4

Calculate the value inside the square root.
$(22)=\sqrt{88 +33}$

STEP 5

Add the values inside the square root.
$(22)=\sqrt{121}$

STEP 6

Finally, calculate the square root of $121$ .
$(22)=\sqrt{121} =11$ So, $(22) =11$ .

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QuestionEvaluate $E(22)$ for the function $E(x)=\sqrt{4x+33}$ . What is $E(22)$ ?

Studdy Solution

STEP 1

Assumptions1. The function is $(x)=\sqrt{4 x+33}$ . We need to evaluate $(22)$

STEP 2

We can evaluate $(22)$ by substituting $x$ with $22$ in the function.
$(22)=\sqrt{4(22)+33}$

STEP 3

First, calculate the value inside the square root by multiplying $$ with $22$ and then adding $33$.
$(22)=\sqrt{ \times22 +33}$

STEP 4

Calculate the value inside the square root.
$(22)=\sqrt{88 +33}$

STEP 5

Add the values inside the square root.
$(22)=\sqrt{121}$

STEP 6

Finally, calculate the square root of $121$ .
$(22)=\sqrt{121} =11$ So, $(22) =11$ .

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QuestionEvaluate E(22)E(22)E(22) for the function E(x)=4x+33E(x)=\sqrt{4x+33}E(x)=4x+33​. What is E(22)E(22)E(22)?

Studdy Solution

STEP 1

Assumptions1. The function is (x)=4x+33(x)=\sqrt{4 x+33}(x)=4x+33​ . We need to evaluate (22)(22)(22)

STEP 2

We can evaluate (22)(22)(22) by substituting xxx with 222222 in the function.(22)=4(22)+33(22)=\sqrt{4(22)+33}(22)=4(22)+33​

STEP 3

First, calculate the value inside the square root by multiplying $$ with $22$ and then adding $33$.(22)=×22+33(22)=\sqrt{ \times22 +33}(22)=×22+33​

STEP 4

Calculate the value inside the square root.(22)=88+33(22)=\sqrt{88 +33}(22)=88+33​

STEP 5

Add the values inside the square root.(22)=121(22)=\sqrt{121}(22)=121​

STEP 6

Finally, calculate the square root of 121121121.(22)=121=11(22)=\sqrt{121} =11(22)=121​=11So, (22)=11(22) =11(22)=11.

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QuestionEvaluate $E(22)$ for the function $E(x)=\sqrt{4x+33}$ . What is $E(22)$ ?

Assumptions1. The function is $(x)=\sqrt{4 x+33}$ . We need to evaluate $(22)$

We can evaluate $(22)$ by substituting $x$ with $22$ in the function.
$(22)=\sqrt{4(22)+33}$

First, calculate the value inside the square root by multiplying $$ with $22$ and then adding $33$.
$(22)=\sqrt{ \times22 +33}$

Calculate the value inside the square root.
$(22)=\sqrt{88 +33}$

Add the values inside the square root.
$(22)=\sqrt{121}$

Finally, calculate the square root of $121$ .
$(22)=\sqrt{121} =11$ So, $(22) =11$ .