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Math  /  Numbers & Operations

QuestionE=(6.626×10−34 s.5)(6.00×1011 Hz)E=\left(6.626 \times 10^{-34} \mathrm{~s} .5\right)\left(6.00 \times 10^{11} \mathrm{~Hz}\right)

Studdy Solution

STEP 1

1. We are given two values to multiply: 6.626×10−34 s6.626 \times 10^{-34} \, \text{s} and 6.00×1011 Hz6.00 \times 10^{11} \, \text{Hz}.
2. We need to calculate the product of these two values to find EE.

STEP 2

1. Identify the components of the expression.
2. Multiply the numerical coefficients.
3. Apply the laws of exponents to the powers of 10.
4. Combine the results to find the final value of EE.

STEP 3

Identify the components of the expression:
- Numerical coefficient: 6.6266.626 - Power of 10: 10−3410^{-34} - Numerical coefficient: 6.006.00 - Power of 10: 101110^{11}

STEP 4

Multiply the numerical coefficients:
6.626×6.00=39.756 6.626 \times 6.00 = 39.756

STEP 5

Apply the laws of exponents to the powers of 10:
10−34×1011=10−34+11=10−23 10^{-34} \times 10^{11} = 10^{-34 + 11} = 10^{-23}

STEP 6

Combine the results to find the final value of EE:
E=39.756×10−23 E = 39.756 \times 10^{-23}
To express this in standard scientific notation, adjust the coefficient:
E=3.9756×10−22 E = 3.9756 \times 10^{-22}
The calculated value of EE is:
3.9756×10−22\boxed{3.9756 \times 10^{-22}}

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