Math

QuestionGraph f(x)=x+3x+3f(x)=\frac{|x+3|}{x+3} for xx in the range [4,4][-4,4].

Studdy Solution

STEP 1

Assumptions1. We are sketching the graph of the function f(x)=x+3x+3f(x)=\frac{|x+3|}{x+3}. . We are sketching the graph on the interval [4,4][-4,4].

STEP 2

The function f(x)=x+x+f(x)=\frac{|x+|}{x+} can be split into two cases, depending on whether x+x+ is positive or negative.1. When x+0x+ \geq0, x+=x+|x+| = x+, so f(x)=1f(x)=1.
2. When x+<0x+ <0, x+=(x+)|x+| = -(x+), so f(x)=1f(x)=-1.

STEP 3

The point where x+3=0x+3=0 is x=3x=-3. This is the point where the function changes from 1-1 to 11.

STEP 4

Now, we can sketch the graph. For x[4,3)x \in [-4,-3), f(x)=1f(x)=-1. For x(3,4]x \in (-3,4], f(x)=1f(x)=1. At x=3x=-3, the function is not defined.

STEP 5

To make the sketch clearer, we can mark the points (4,1)(-4,-1), (3,1)(-3,-1), (3,1)(-3,1), and (4,1)(4,1) on the graph. Draw a solid line from (4,1)(-4,-1) to (3,1)(-3,-1), and another solid line from (3,1)(-3,1) to (4,1)(4,1). Leave a hole at (3,1)(-3,-1) and (3,1)(-3,1) to indicate that the function is not defined at x=3x=-3.
The graph of f(x)=x+3x+3f(x)=\frac{|x+3|}{x+3} on the interval [4,4][-4,4] has been sketched.

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