Math

QuestionConstruct DE\overline{\mathrm{DE}} such that DE=TR+PS\mathrm{DE}=\mathrm{TR}+\mathrm{PS}. What is the third step in the construction?

Studdy Solution

STEP 1

Assumptions1. We are given two line segments TR\overline{\mathrm{TR}} and PS\overline{\mathrm{PS}}. . We are asked to construct a line segment DE\overline{\mathrm{DE}} such that DE=TR+PS\mathrm{DE}=\mathrm{TR}+\mathrm{PS}.
3. The steps A, B, and D are given, and we are asked to find the third step of the construction.

STEP 2

The first step A tells us to open the compass to the length of TS\overline{\mathrm{TS}}. However, we don't have a line segment TS\overline{\mathrm{TS}} in our assumptions. This seems to be a typo, and it should be PS\overline{\mathrm{PS}}.

STEP 3

The second step B tells us to place the compass at point (or (or ) and draw an arc through (or (or ). This step is not clear, as we don't have points and and on the same line segment. This seems to be another typo, and it should be to place the compass at point (or (or ) and draw an arc through (or (or ).

STEP 4

The fourth step D tells us to open the compass to the length of TR\overline{\mathrm{TR}}. This step is clear and doesn't seem to have any typos.

STEP 5

Now, we need to find the third step of the construction. Looking at the options given, we can rule out option A and C, as they mention adding another ray, which is not necessary in this construction.

STEP 6

Option B seems to be the most logical next step. With the same compass setting as in step A (which should be the length of PS\overline{\mathrm{PS}}), we should put the compass point on the endpoint of the construction in the first step and draw an arc that intersects the previous arc. This will give us the point $$ on the line segment $\overline{\mathrm{DE}}$.
So, the third step of the construction is With the same compass setting, put the compass point on the endpoint of the construction in the first step and draw an arc that intersects the previous arc.

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