Math  /  Algebra

QuestionDetermine whether the function is one-to-one. f(x)=x+4f(x)=|x+4|
Is the function one-to-one? Yes No

Studdy Solution

STEP 1

What is this asking? Is there only one xx value for every yy value in the function f(x)=x+4f(x) = |x+4|? Watch out! Absolute value functions can be tricky!
Remember they create "V" shapes and that can lead to the same yy value for different xx values.

STEP 2

1. Understand One-to-One
2. Test the Function

STEP 3

A **one-to-one** function means that for every yy value, there's only one xx value that can produce it.
Think of it like a special club where each member has a unique secret code.
No two members share the same code!

STEP 4

Let's pick a **positive** number for f(x)f(x), say f(x)=2f(x) = 2.

STEP 5

x+4=2 |x+4| = 2 This means x+4x+4 could equal **positive 2** or **negative 2**.

STEP 6

If x+4=2x+4 = 2, then x=24=2x = 2 - 4 = \mathbf{-2}.

STEP 7

If x+4=2x+4 = -2, then x=24=6x = -2 - 4 = \mathbf{-6}.

STEP 8

Whoa! We found **two different** xx values (2-2 and 6-6) that give us the same f(x)f(x) value of 22.
This breaks our "one xx for every yy" rule!

STEP 9

No, the function f(x)=x+4f(x) = |x+4| is **not one-to-one**.

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