Math  /  Geometry

QuestionDetermine the value of x. 147147^\circ x+42x + 42^\circ 2x2x

Studdy Solution

STEP 1

What is this asking? We need to find the value of xx in a triangle with angles x+42x + 42 degrees and 2x2x degrees, given an **exterior angle** of 147147 degrees. Watch out! Don't forget that the sum of the angles in a triangle is 180180 degrees, and remember the relationship between **exterior** and **interior** angles!

STEP 2

1. Find the third interior angle.
2. Set up an equation using the triangle angle sum.
3. Solve for xx.

STEP 3

An **exterior angle** of a triangle is equal to the sum of the two non-adjacent **interior angles**.
Our exterior angle is 147147 degrees.

STEP 4

Let's call the third interior angle aa.
We know that 147=a+2x147^\circ = a + 2x^\circ, so a=1472xa = 147^\circ - 2x^\circ.

STEP 5

So, we can write the equation: (x+42)+(2x)+(1472x)=180(x + 42)^\circ + (2x)^\circ + (147 - 2x)^\circ = 180^\circ.

STEP 6

We have x+42+2x+1472x=180x + 42 + 2x + 147 - 2x = 180.
Combining like terms, we get x+189=180x + 189 = 180.

STEP 7

Subtract 189189 from both sides of the equation: x+189189=180189x + 189 - 189 = 180 - 189.
This gives us x=9x = -9.

STEP 8

The value of xx is 9-9.

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