Math

QuestionFind the domain of (st)(x)=1x+6(s \cdot t)(x)=\frac{-1}{x+6}, where s(x)=x3x236s(x)=\frac{x-3}{x^{2}-36} and t(x)=x63xt(x)=\frac{x-6}{3-x}.

Studdy Solution

STEP 1

Assumptions1. The product function is (st)(x)=1x+6(s \cdot t)(x)=\frac{-1}{x+6}, where s(x)=x3x36s(x)=\frac{x-3}{x^{}-36} and t(x)=x63xt(x)=\frac{x-6}{3-x}.. The domain of a function is the set of all possible input values (x-values) which will output real numbers.

STEP 2

First, we need to find the domain of each function s(x)s(x) and t(x)t(x). The domain of a function is the set of all real numbers for which the function is defined. For a rational function, the function is undefined when the denominator is equal to zero.
For s(x)s(x), we set the denominator equal to zero and solve for xx.
x236=0x^{2}-36=0

STEP 3

olve the equation x236=0x^{2}-36=0 for xx.
x2=36x^{2}=36x=±36x=\pm\sqrt{36}x=±6x=\pm6

STEP 4

So, the function s(x)s(x) is undefined at x=6x=6 and x=6x=-6. Therefore, the domain of s(x)s(x) is all real numbers except 66 and 6-6.
Now, let's find the domain of t(x)t(x). Set the denominator equal to zero and solve for xx.
3x=03-x=0

STEP 5

olve the equation 3x=03-x=0 for xx.
x=3x=3

STEP 6

So, the function t(x)t(x) is undefined at x=3x=3. Therefore, the domain of t(x)t(x) is all real numbers except 33.

STEP 7

Now, let's find the domain of the product function (st)(x)(s \cdot t)(x). Set the denominator equal to zero and solve for xx.
x+6=0x+6=0

STEP 8

olve the equation x+6=0x+6=0 for xx.
x=6x=-6

STEP 9

So, the function (st)(x)(s \cdot t)(x) is undefined at x=6x=-6. Therefore, the domain of (st)(x)(s \cdot t)(x) is all real numbers except 6-6.

STEP 10

Finally, to find the domain of the product function (st)(x)(s \cdot t)(x), we need to consider the domains of s(x)s(x), t(x)t(x), and (st)(x)(s \cdot t)(x). The domain of the product function is the intersection of the domains of s(x)s(x), t(x)t(x), and (st)(x)(s \cdot t)(x).
The domain of the product function (st)(x)(s \cdot t)(x) is all real numbers except 6-6, 66, and 33.

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