Math  /  Calculus

QuestionDetermine the horizontal asymptote of the function. If none exists, state that fact. f(x)=2x34x+56x3+9x5f(x)=\frac{2 x^{3}-4 x+5}{6 x^{3}+9 x-5}
Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. A. The function has one horizontal asymptote, \square (Type an equation.) B. The function has two horizontal asymptotes. The top asymptote is \square and the bottom asymptote is \square (Type equations.) C. The function has no horizontal asymptotes.

Studdy Solution

STEP 1

1. A horizontal asymptote of a rational function f(x)=P(x)Q(x) f(x) = \frac{P(x)}{Q(x)} is determined by the degrees of the polynomials P(x) P(x) and Q(x) Q(x) .
2. If the degree of P(x) P(x) is less than the degree of Q(x) Q(x) , the horizontal asymptote is y=0 y = 0 .
3. If the degree of P(x) P(x) is equal to the degree of Q(x) Q(x) , the horizontal asymptote is y=ab y = \frac{a}{b} , where a a and b b are the leading coefficients of P(x) P(x) and Q(x) Q(x) , respectively.
4. If the degree of P(x) P(x) is greater than the degree of Q(x) Q(x) , there is no horizontal asymptote.

STEP 2

1. Identify the degrees of the numerator and the denominator.
2. Compare the degrees to determine the presence and equation of a horizontal asymptote.

STEP 3

Identify the degrees of the numerator and the denominator:
The numerator is 2x34x+5 2x^3 - 4x + 5 , and its degree is 3. The denominator is 6x3+9x5 6x^3 + 9x - 5 , and its degree is 3.

STEP 4

Compare the degrees of the numerator and the denominator:
Since the degree of the numerator (3) is equal to the degree of the denominator (3), we use the leading coefficients to determine the horizontal asymptote.

STEP 5

Find the leading coefficients:
The leading coefficient of the numerator is 2. The leading coefficient of the denominator is 6.
The horizontal asymptote is given by:
y=26=13 y = \frac{2}{6} = \frac{1}{3}
The function has one horizontal asymptote, y=13 y = \frac{1}{3} .

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