QuestionDetermine the chemical symbols for the neutral elements corresponding to the electronic configurations. Use proper formatting; letter case matters. $1 s^{2} 2 s^{2} 2 p^{3}:$ Incorrect Answer $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6}:$ $\square$ Incorrect Answer $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}:$ $\square$ Incorrect Answer $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}:$ $\square$ Incorrect Answer

Studdy Solution

STEP 1

What is this asking? Given some electron configurations, what are the corresponding elements? Watch out! Remember, the superscripts tell you how many electrons are in each subshell, and the order matters!

STEP 2

1. Nitrogen
2. Krypton
3. Argon
4. Phosphorus

STEP 3

Alright, let's decode this first electron configuration: $1s^2 2s^2 2p^3$ .
Each part of this tells us something important!

STEP 4

The numbers ( $1$ , $2$ , etc.) tell us the energy level, or shell, of the electrons. $1$ is the lowest energy level, closest to the nucleus, and the numbers get bigger as we move further out.

STEP 5

The letters ( $s$ , $p$ , etc.) tell us the shape of the electron's orbital within that energy level. $s$ orbitals are spherical, $p$ orbitals are dumbbell-shaped, and so on.

STEP 6

The superscripts ( $2$ , $3$ , etc.) tell us how many electrons are in that specific orbital.
So, $1s^2$ means there are two electrons in the $1s$ orbital.

STEP 7

Now, let's add up all those superscripts! $2 + 2 + 3 = 7$ .
This means we're looking for an element with seven electrons, which also means it has seven protons, since neutral atoms have the same number of protons and electrons.

STEP 8

The element with seven protons is nitrogen, and its chemical symbol is N.
Boom!

STEP 9

Let's tackle the next one: $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6$ .
Looks long, but the same principles apply!

STEP 10

Add up those superscripts: $2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 = 36$ .
So, we're looking for an element with 36 electrons, and therefore 36 protons.

STEP 11

That's krypton, with the chemical symbol Kr!

STEP 12

Next up: $1s^2 2s^2 2p^6 3s^2 3p^6$ .
Let's sum those superscripts: $2 + 2 + 6 + 2 + 6 = 18$ .

STEP 13

18 electrons means 18 protons, which corresponds to argon, or Ar!

STEP 14

Finally, we have $1s^2 2s^2 2p^6 3s^2 3p^3$ . Adding the superscripts gives us $2 + 2 + 6 + 2 + 3 = 15$ .

STEP 15

An element with 15 electrons and 15 protons is phosphorus, and its symbol is P.
Fantastic!

STEP 16

$1 s^{2} 2 s^{2} 2 p^{3}:$ N $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6}:$ Kr $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}:$ Ar $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}:$ P

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Studdy Solution

STEP 1

What is this asking? Given some electron configurations, what are the corresponding elements? Watch out! Remember, the superscripts tell you how many electrons are in each subshell, and the order matters!

STEP 2

1. Nitrogen
2. Krypton
3. Argon
4. Phosphorus

STEP 3

Alright, let's decode this first electron configuration: $1s^2 2s^2 2p^3$ .
Each part of this tells us something important!

STEP 4

The numbers ( $1$ , $2$ , etc.) tell us the energy level, or shell, of the electrons. $1$ is the lowest energy level, closest to the nucleus, and the numbers get bigger as we move further out.

STEP 5

The letters ( $s$ , $p$ , etc.) tell us the shape of the electron's orbital within that energy level. $s$ orbitals are spherical, $p$ orbitals are dumbbell-shaped, and so on.

STEP 6

The superscripts ( $2$ , $3$ , etc.) tell us how many electrons are in that specific orbital.
So, $1s^2$ means there are two electrons in the $1s$ orbital.

STEP 7

Now, let's add up all those superscripts! $2 + 2 + 3 = 7$ .
This means we're looking for an element with seven electrons, which also means it has seven protons, since neutral atoms have the same number of protons and electrons.

STEP 8

The element with seven protons is nitrogen, and its chemical symbol is N.
Boom!

STEP 9

Let's tackle the next one: $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6$ .
Looks long, but the same principles apply!

STEP 10

Add up those superscripts: $2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 = 36$ .
So, we're looking for an element with 36 electrons, and therefore 36 protons.

STEP 11

That's krypton, with the chemical symbol Kr!

STEP 12

Next up: $1s^2 2s^2 2p^6 3s^2 3p^6$ .
Let's sum those superscripts: $2 + 2 + 6 + 2 + 6 = 18$ .

STEP 13

18 electrons means 18 protons, which corresponds to argon, or Ar!

STEP 14

Finally, we have $1s^2 2s^2 2p^6 3s^2 3p^3$ . Adding the superscripts gives us $2 + 2 + 6 + 2 + 3 = 15$ .

STEP 15

An element with 15 electrons and 15 protons is phosphorus, and its symbol is P.
Fantastic!

STEP 16

$1 s^{2} 2 s^{2} 2 p^{3}:$ N $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6}:$ Kr $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}:$ Ar $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}:$ P

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Studdy Solution

STEP 1

What is this asking? Given some electron configurations, what are the corresponding elements? Watch out! Remember, the superscripts tell you how many electrons are in each subshell, and the order matters!

STEP 2

1. Nitrogen2. Krypton3. Argon4. Phosphorus

STEP 3

Alright, let's **decode** this first electron configuration: 1s22s22p31s^2 2s^2 2p^31s22s22p3.Each *part* of this tells us something important!

STEP 4

The **numbers** (111, 222, etc.) tell us the **energy level**, or shell, of the electrons. 111 is the lowest energy level, closest to the nucleus, and the numbers get bigger as we move further out.

STEP 5

The **letters** (sss, ppp, etc.) tell us the **shape** of the electron's orbital within that energy level. sss orbitals are spherical, ppp orbitals are dumbbell-shaped, and so on.

STEP 6

The **superscripts** (222, 333, etc.) tell us *how many* **electrons** are in that specific orbital.So, 1s21s^21s2 means there are **two** electrons in the 1s1s1s orbital.

STEP 7

Now, let's **add up** all those superscripts! 2+2+3=72 + 2 + 3 = 72+2+3=7.This means we're looking for an element with **seven** electrons, which also means it has **seven** protons, since neutral atoms have the same number of protons and electrons.

STEP 8

The element with **seven** protons is **nitrogen**, and its chemical symbol is **N**.Boom!

STEP 9

Let's tackle the next one: 1s22s22p63s23p64s23d104p61s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^61s22s22p63s23p64s23d104p6.Looks long, but the same principles apply!

STEP 10

**Add up** those superscripts: 2+2+6+2+6+2+10+6=362 + 2 + 6 + 2 + 6 + 2 + 10 + 6 = 362+2+6+2+6+2+10+6=36.So, we're looking for an element with **36** electrons, and therefore **36** protons.

STEP 11

That's **krypton**, with the chemical symbol **Kr**!

STEP 12

Next up: 1s22s22p63s23p61s^2 2s^2 2p^6 3s^2 3p^61s22s22p63s23p6.Let's **sum** those superscripts: 2+2+6+2+6=182 + 2 + 6 + 2 + 6 = 182+2+6+2+6=18.

STEP 13

**18** electrons means **18** protons, which corresponds to **argon**, or **Ar**!

STEP 14

Finally, we have 1s22s22p63s23p31s^2 2s^2 2p^6 3s^2 3p^31s22s22p63s23p3. **Adding** the superscripts gives us 2+2+6+2+3=152 + 2 + 6 + 2 + 3 = 152+2+6+2+3=15.

STEP 15

An element with **15** electrons and **15** protons is **phosphorus**, and its symbol is **P**.Fantastic!

STEP 16

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1. Nitrogen
2. Krypton
3. Argon
4. Phosphorus

Alright, let's decode this first electron configuration: $1s^2 2s^2 2p^3$ .
Each part of this tells us something important!

The numbers ( $1$ , $2$ , etc.) tell us the energy level, or shell, of the electrons. $1$ is the lowest energy level, closest to the nucleus, and the numbers get bigger as we move further out.

The letters ( $s$ , $p$ , etc.) tell us the shape of the electron's orbital within that energy level. $s$ orbitals are spherical, $p$ orbitals are dumbbell-shaped, and so on.

The superscripts ( $2$ , $3$ , etc.) tell us how many electrons are in that specific orbital.
So, $1s^2$ means there are two electrons in the $1s$ orbital.

Now, let's add up all those superscripts! $2 + 2 + 3 = 7$ .
This means we're looking for an element with seven electrons, which also means it has seven protons, since neutral atoms have the same number of protons and electrons.

The element with seven protons is nitrogen, and its chemical symbol is N.
Boom!

Let's tackle the next one: $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6$ .
Looks long, but the same principles apply!

Add up those superscripts: $2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 = 36$ .
So, we're looking for an element with 36 electrons, and therefore 36 protons.

That's krypton, with the chemical symbol Kr!

Next up: $1s^2 2s^2 2p^6 3s^2 3p^6$ .
Let's sum those superscripts: $2 + 2 + 6 + 2 + 6 = 18$ .

18 electrons means 18 protons, which corresponds to argon, or Ar!

Finally, we have $1s^2 2s^2 2p^6 3s^2 3p^3$ . Adding the superscripts gives us $2 + 2 + 6 + 2 + 3 = 15$ .

An element with 15 electrons and 15 protons is phosphorus, and its symbol is P.
Fantastic!