Math  /  Algebra

QuestionDance 5th Period
Evaluate the left hand side to find the value of aa in the equation in simplest forn x32x25=xa\frac{x^{\frac{3}{2}}}{x^{\frac{2}{5}}}=x^{a}

Studdy Solution

STEP 1

1. The equation involves simplifying an expression with exponents.
2. The properties of exponents will be used to simplify the expression.

STEP 2

1. Apply the quotient rule for exponents.
2. Simplify the expression to find the value of a a .

STEP 3

Apply the quotient rule for exponents, which states that xmxn=xmn\frac{x^m}{x^n} = x^{m-n}. In this case, m=32m = \frac{3}{2} and n=25n = \frac{2}{5}:
x32x25=x(3225)\frac{x^{\frac{3}{2}}}{x^{\frac{2}{5}}} = x^{\left(\frac{3}{2} - \frac{2}{5}\right)}

STEP 4

To simplify 3225\frac{3}{2} - \frac{2}{5}, find a common denominator. The least common denominator of 2 and 5 is 10:
32=1510,25=410\frac{3}{2} = \frac{15}{10}, \quad \frac{2}{5} = \frac{4}{10}
Now subtract the fractions:
3225=1510410=1110\frac{3}{2} - \frac{2}{5} = \frac{15}{10} - \frac{4}{10} = \frac{11}{10}

STEP 5

Substitute the simplified exponent back into the expression:
x(3225)=x1110x^{\left(\frac{3}{2} - \frac{2}{5}\right)} = x^{\frac{11}{10}}
Thus, the value of a a is:
a=1110a = \frac{11}{10}
The value of a a is:
1110 \boxed{\frac{11}{10}}

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