Math  /  Geometry

Questiond. A painter is covering a rectangular wall with dimensions of 4 meters by 3 meters using a special paint that comes in a 50 -liter container. Each liter of paint covers 10 square meters, and the wall requires two coats of paint. After painting this wall, what percent of the paint will be left in the container?

Studdy Solution

STEP 1

What is this asking? How much paint is left over after painting a wall twice, and what percentage of the original container is that? Watch out! Don't forget the wall needs *two* coats of paint!

STEP 2

1. Calculate the wall's area.
2. Calculate the total paint needed.
3. Calculate the remaining paint.
4. Calculate the percentage of remaining paint.

STEP 3

Alright, let's **start** by finding the area of the wall!
We know it's a rectangle, and the area of a rectangle is length times width.
So, we have 44 meters multiplied by 33 meters.

STEP 4

43=12 4 \cdot 3 = 12 So, the area of the wall is **1212 square meters**.

STEP 5

Now, remember, we need *two* coats of paint.
So, we multiply the wall's area by 22: 122=24 12 \cdot 2 = 24 That's **2424 square meters** of paint needed in total!

STEP 6

We know that 11 liter of paint covers 1010 square meters.
So, to find out how many liters we need, we divide the total area we need to paint by the area covered by one liter: 24÷10=2.4 24 \div 10 = 2.4 We need **2.42.4 liters** of paint.

STEP 7

We started with a **5050-liter** container and used 2.42.4 liters.
To find out how much is left, we subtract: 502.4=47.6 50 - 2.4 = 47.6 We have **47.647.6 liters** of paint left!

STEP 8

To find the percentage, we divide the remaining paint by the original amount and multiply by 100100: 47.650100 \frac{47.6}{50} \cdot 100

STEP 9

0.952100=95.2 0.952 \cdot 100 = 95.2 So, there's **95.2%95.2\%** of the paint left in the container!

STEP 10

95.2%95.2\% of the paint is left in the container.

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