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QuestionFind the correct yy values for the line y=−14x−1y=-\frac{1}{4} x-1. Which table matches the equation?

Studdy Solution

STEP 1

Assumptions1. The equation of the straight line is y=−14x−1y=-\frac{1}{4} x-1 . We need to find the correct values of yy for the given values of xx in the tables

STEP 2

We will start by checking the values in the first table. Let's substitute x=−4x=-4 into the equation and see if we get y=0y=0.
y=−14×−4−1y=-\frac{1}{4} \times -4 -1

STEP 3

Calculate the value of yy when x=−x=-.
y=1−1=0y=1 -1 =0

STEP 4

The first value in the first table is correct. Now, let's check the second value. Substitute x=−1x=-1 into the equation and see if we get y=−34y=-\frac{3}{4}.
y=−14×−1−1y=-\frac{1}{4} \times -1 -1

STEP 5

Calculate the value of yy when x=−1x=-1.
y=14−1=−34y= \frac{1}{4} -1 = -\frac{3}{4}

STEP 6

The second value in the first table is correct. Now, let's check the third value. Substitute x=3x=3 into the equation and see if we get y=−134y=-1\frac{3}{4}.
y=−14×3−1y=-\frac{1}{4} \times3 -1

STEP 7

Calculate the value of yy when x=3x=3.
y=−34−1=−134y= -\frac{3}{4} -1 = -1\frac{3}{4}

STEP 8

All the values in the first table are correct. Now, let's check the values in the second table. Substitute x=−7x=-7 into the equation and see if we get y=−34y=-\frac{3}{4}.
y=−14×−7−1y=-\frac{1}{4} \times -7 -1

STEP 9

Calculate the value of yy when x=−7x=-7.
y=74−=34y= \frac{7}{4} - = \frac{3}{4}

STEP 10

The first value in the second table is incorrect. Now, let's check the second value. Substitute x=−5x=-5 into the equation and see if we get y=−4y=-\frac{}{4}.
y=−4×−5−y=-\frac{}{4} \times -5 -

STEP 11

Calculate the value of yy when x=−5x=-5.
y=54−=4y= \frac{5}{4} - = \frac{}{4}The second value in the second table is also incorrect. Therefore, the correct table is the first one (option a).

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