Math  /  Algebra

QuestionConsider the following lines. Line 1: 3x4y=123 x-4 y=12 Line 2: a line perpendicular to 3x4y=123 x-4 y=12 that contains the point (3,4)(3,-4) Write the equation of Line 1 in slope-intercept form. \square Find the slope of Line 1. \square

Studdy Solution

STEP 1

1. Line 1 is given in standard form, and we need to convert it to slope-intercept form.
2. The slope-intercept form of a line is given by y=mx+b y = mx + b , where m m is the slope and b b is the y-intercept.
3. The slope of a line perpendicular to another line is the negative reciprocal of the slope of the original line.

STEP 2

1. Convert the equation of Line 1 from standard form to slope-intercept form.
2. Determine the slope of Line 1 from the slope-intercept form.

STEP 3

Start with the equation of Line 1 in standard form:
3x4y=12 3x - 4y = 12
Solve for y y to convert it to slope-intercept form. First, isolate the term with y y :
4y=3x+12 -4y = -3x + 12

STEP 4

Divide each term by 4-4 to solve for y y :
y=34x3 y = \frac{3}{4}x - 3
Now, the equation is in slope-intercept form, where the slope m m is 34\frac{3}{4} and the y-intercept b b is 3-3.

STEP 5

Identify the slope of Line 1 from the slope-intercept form:
The slope m m of Line 1 is 34\frac{3}{4}.
The equation of Line 1 in slope-intercept form is:
y=34x3 y = \frac{3}{4}x - 3
The slope of Line 1 is:
34 \frac{3}{4}

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