QuestionConsider the following iteration statement:
```
int own = 1;
int lcv = 10;
while ( lcv >= 0)
{
own+=2;
lcv--;
```
}
What is the value of own after the for loop terminates?
own =11
Studdy Solution
STEP 1
What is this asking? How many times does a counter increase inside a loop, and what's its final value? Watch out! Don't forget to account for the initial value of the counter *outside* the loop!
STEP 2
1. Analyze the loop
2. Calculate the final value
STEP 3
Alright, so we have this loop that's gonna run as long as `lcv` is greater than or equal to zero. `lcv` starts at **10** and goes down by **1** each time.
That's like a countdown, right?
STEP 4
How many times will the loop run?
Well, it starts at **10** and goes down to **0**, hitting every number in between.
That's **11** times total! .
STEP 5
Inside the loop, `own` increases by **2** each time.
So, the loop runs **11** times, and `own` gets a boost of **2** each time.
STEP 6
`own` starts at **1** *before* the loop even begins.
This is super important!
STEP 7
The loop runs **11** times, and `own` increases by **2** each time.
That means the total increase from the loop is .
STEP 8
So, we start with **1** and add **22** from the loop.
The final value is .
Boom!
STEP 9
The final value of `own` is **23**.
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