Math  /  Data & Statistics

QuestionConsider the below data for ALL PARTS of this question: 788392688578 \quad 83926885
What is the INNER QUARTILE RANGE? \qquad Note: Enter X.X AT LEAST ONE DIGIT BEFORE THE DECIMAL, ONE AFTER and round up AFTER all calculations. Thus, 7 is entered as 7.0; -3.562 is entered as -3.6 ; 0.3750 is entered as 0.4;17.3510.4 ; 17.351 is entered as 17.4 \square A

Studdy Solution

STEP 1

What is this asking? Find the difference between the **75th percentile** and the **25th percentile** of this small dataset. Watch out! Don't forget to **sort the data** before finding the quartiles!
Also, remember to round up at the very end, not during intermediate steps.

STEP 2

1. Sort the data
2. Find the 25th percentile (Q1)
3. Find the 75th percentile (Q3)
4. Calculate the Interquartile Range (IQR)

STEP 3

Alright, let's **wrangle these numbers** into order from least to greatest!
We've got 68,78,83,85,9268, 78, 83, 85, 92.
Much better!
This makes it way easier to see where the quartiles are.

STEP 4

Since we have **5 data points**, the position of the **25th percentile (Q1)** is (5+1)25100=60.25=1.5(5 + 1) \cdot \frac{25}{100} = 6 \cdot 0.25 = 1.5.
This means Q1 is between the **1st and 2nd values**.

STEP 5

To find Q1, we'll take the average of the 1st and 2nd values: 68+782=1462=73\frac{68 + 78}{2} = \frac{146}{2} = 73.
So, our **Q1 is 73**!

STEP 6

Similarly, the position of the **75th percentile (Q3)** is (5+1)75100=60.75=4.5(5 + 1) \cdot \frac{75}{100} = 6 \cdot 0.75 = 4.5.
This puts Q3 right between the **4th and 5th values**.

STEP 7

Let's average those values to find Q3: 85+922=1772=88.5\frac{85 + 92}{2} = \frac{177}{2} = 88.5.
So, **Q3 is 88.5**!

STEP 8

The **Interquartile Range (IQR)** is simply the difference between Q3 and Q1.
So, IQR=Q3Q1=88.573=15.5IQR = Q3 - Q1 = 88.5 - 73 = 15.5.

STEP 9

Since the problem asked us to round up after all calculations, and our result has exactly one digit after the decimal, we don't need to change anything!
Our **final IQR is 15.5**!

STEP 10

The **Interquartile Range** is **15.5**.

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