Math  /  Calculus

QuestionConsider 8x6+48x(x5+1)d:\int \sqrt{8 x^{6}+48 x} \cdot\left(x^{5}+1\right) d: What is the most appropriate u-substitution? 8x6+48x8 x^{6}+48 x x5+1x^{5}+1 u=xu=\sqrt{x} u=xu=x

Studdy Solution

STEP 1

What is this asking? We need to find the best *u*-substitution to simplify this scary-looking integral! Watch out! Don't get tricked by the complexity of the expression.
Sometimes the simplest substitutions are the most effective.

STEP 2

1. Analyze the integrand
2. Propose a *u*-substitution
3. Test the substitution

STEP 3

Let's take a closer look at what we're dealing with.
We have an integral with a square root term, 8x6+48x\sqrt{8x^6 + 48x}, multiplied by (x5+1)(x^5 + 1).
It looks complicated, but don't worry, we'll break it down!

STEP 4

Notice the expression inside the square root: 8x6+48x8x^6 + 48x.
We can **factor out** 8x8x to get 8x(x5+6)8x(x^5 + 6).
This is a good sign!
See how it relates to the other term (x5+1)(x^5 + 1)?
They both have an x5x^5 term.
This similarity is a huge clue for our *u*-substitution.

STEP 5

Let's try u=8x6+48xu = 8x^6 + 48x.
This seems like a good starting point because it's the expression inside the square root.

STEP 6

If u=8x6+48xu = 8x^6 + 48x, then the **derivative** is dudx=48x5+48\frac{du}{dx} = 48x^5 + 48.
We can **factor out** 4848 to get dudx=48(x5+1)\frac{du}{dx} = 48(x^5 + 1).
This means du=48(x5+1)dxdu = 48(x^5 + 1) dx.

STEP 7

Now, we can **rewrite** our integral in terms of *u*.
We have 8x6+48x\sqrt{8x^6 + 48x} which is just u\sqrt{u}.
Also, we have (x5+1)dx(x^5 + 1)dx which is 148du\frac{1}{48} du.

STEP 8

Putting it all together, our integral becomes u148du=148u12du. \int \sqrt{u} \cdot \frac{1}{48} du = \frac{1}{48} \int u^{\frac{1}{2}} du.

STEP 9

This is much simpler to integrate!
We can use the **power rule** to integrate u12u^{\frac{1}{2}}.
Remember, the power rule says xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C, where *C* is the **constant of integration**.

STEP 10

Applying the power rule, we get 148u12du=148u12+112+1+C=148u3232+C=14823u32+C=172u32+C. \frac{1}{48} \int u^{\frac{1}{2}} du = \frac{1}{48} \cdot \frac{u^{\frac{1}{2} + 1}}{\frac{1}{2} + 1} + C = \frac{1}{48} \cdot \frac{u^{\frac{3}{2}}}{\frac{3}{2}} + C = \frac{1}{48} \cdot \frac{2}{3} u^{\frac{3}{2}} + C = \frac{1}{72} u^{\frac{3}{2}} + C.

STEP 11

Finally, **substitute** back u=8x6+48xu = 8x^6 + 48x to get our **final answer**: 172(8x6+48x)32+C. \frac{1}{72} (8x^6 + 48x)^{\frac{3}{2}} + C.

STEP 12

The most appropriate *u*-substitution is u=8x6+48xu = 8x^6 + 48x.

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