Math  /  Algebra

Questioncompute the monthly cost for a subscriber, where xx is the number of C(x)={19.99 if 0<x2500.25x42.51 if x>250C(x)=\left\{\begin{array}{ll} 19.99 & \text { if } 0<x \leq 250 \\ 0.25 x-42.51 & \text { if } x>250 \end{array}\right.
Compute the monthly cost of the cellular phone for use of the followi (a) 150 (b) 300 (c) 251 (a) C(150)=$C(150)=\$ \square (Round to the nearest cent as needed.)

Studdy Solution

STEP 1

1. The cost function C(x)C(x) for the cellular phone usage is piecewise defined.
2. For 0<x2500 < x \leq 250, the cost is a flat rate of \$19.99.
3. For \(x > 250\), the cost is calculated using the linear function \(0.25x - 42.51\).
4. We need to evaluate the cost for specific values of \(x\) and round to the nearest cent if necessary.

STEP 2

1. Evaluate C(x)C(x) for x=150x = 150 using the appropriate piece of the piecewise function.
2. Evaluate C(x)C(x) for x=300x = 300 using the appropriate piece of the piecewise function.
3. Evaluate C(x)C(x) for x=251x = 251 using the appropriate piece of the piecewise function.

STEP 3

Determine which piece of the piecewise function applies for x=150x = 150.
Since 0<1502500 < 150 \leq 250, we use the first piece of the function: C(x)=19.99C(x) = 19.99.

STEP 4

Compute C(150)C(150).
C(150)=19.99 C(150) = 19.99

STEP 5

Determine which piece of the piecewise function applies for x=300x = 300.
Since 300>250300 > 250, we use the second piece of the function: C(x)=0.25x42.51C(x) = 0.25x - 42.51.

STEP 6

Compute C(300)C(300).
C(300)=0.25×30042.51 C(300) = 0.25 \times 300 - 42.51 C(300)=7542.51 C(300) = 75 - 42.51 C(300)=32.49 C(300) = 32.49

STEP 7

Determine which piece of the piecewise function applies for x=251x = 251.
Since 251>250251 > 250, we use the second piece of the function: C(x)=0.25x42.51C(x) = 0.25x - 42.51.

STEP 8

Compute C(251)C(251).
C(251)=0.25×25142.51 C(251) = 0.25 \times 251 - 42.51 C(251)=62.7542.51 C(251) = 62.75 - 42.51 C(251)=20.24 C(251) = 20.24
The monthly costs are as follows: (a) C(150)=$19.99C(150) = \$19.99 (b) C(300)=$32.49C(300) = \$32.49 (c) C(251)=$20.24C(251) = \$20.24

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