Math  /  Data & Statistics

QuestionCompute the least-squares regression equation for the given data set. Use a TI-84 calculator. Round the slope and yy intercept to at least four decimal places. \begin{tabular}{l|lllllll} xx & 5.8 & 4.2 & 6.3 & 4.4 & 6.6 & 5.9 & 5.0 \\ \hlineyy & 1.9 & 4.8 & 0.8 & 3.9 & 1.2 & 1.7 & 3.0 \end{tabular}
Send data to Excel
Regression line equation: y^=\hat{y}= \square

Studdy Solution

STEP 1

What is this asking? We need to find the line that best fits a bunch of points, the least-squares regression line, and give its equation in the form y^=mx+b\hat{y} = mx + b, rounding the slope (mm) and y-intercept (bb) to four decimal places! Watch out! Don't mix up xx and yy values when entering them into your calculator.
Also, make sure your calculator is set to calculate a linear regression!

STEP 2

1. Enter the data
2. Calculate the regression

STEP 3

First, **hit the STAT button** on your calculator.
This takes us to the statistics menu where all the magic happens!

STEP 4

Select **Edit** (usually by pressing 1 or ENTER).
Now, carefully **enter the xx values** into L1 and the **yy values** into L2.
Double-check your entries!
Accuracy is key here.

STEP 5

**Press STAT again**, and then **go over to CALC** (using the right arrow key).

STEP 6

Scroll down to **LinReg(ax+b)** and press ENTER.
This tells the calculator we want a linear regression in the form y=ax+by = ax + b (which is the same as y^=mx+b\hat{y} = mx + b, just with different letters for slope and intercept).

STEP 7

Make sure Xlist is set to L1 and Ylist is set to L2.
If they aren't, change them!
Then, **go down to Calculate** and press ENTER.

STEP 8

The calculator will show you the values for aa (the slope, like mm) and bb (the y-intercept).
It might also show you rr and r2r^2, which tell you how well the line fits the data, but we don't need those for this problem. **Write down the values for aa and bb, rounding to four decimal places**.
For example, if a=0.526123a = -0.526123 and b=4.187654b = 4.187654, we'd write down a0.5261a \approx -0.5261 and b4.1877b \approx 4.1877.

STEP 9

So, if our calculated slope was a0.5261a \approx -0.5261 and our y-intercept was b4.1877b \approx 4.1877, the least-squares regression equation is y^=0.5261x+4.1877\hat{y} = -0.5261x + 4.1877. **Replace these example values with the ones you calculated!**

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