Math

QuestionUse the function f(x)=x4f(x)=\sqrt{x-4} to complete the table. Simplify answers; mark "Not a real number" if needed.

Studdy Solution

STEP 1

Assumptions1. The function is given by f(x)=x4f(x)=\sqrt{x-4} . We need to find the values of f(x)f(x) for various values of xx
3. If x4x-4 is less than0, the value of f(x)f(x) is not a real number because the square root of a negative number is not a real number.

STEP 2

Let's start by finding f(x)f(x) for x=4x=4. We substitute x=4x=4 into the function.
f(4)=44f(4)=\sqrt{4-4}

STEP 3

implify the expression inside the square root.
f()=0f()=\sqrt{0}

STEP 4

Calculate the square root.
f(4)=0f(4)=0

STEP 5

Now, let's find f(x)f(x) for x=5x=5. We substitute x=5x=5 into the function.
f(5)=54f(5)=\sqrt{5-4}

STEP 6

implify the expression inside the square root.
f(5)=1f(5)=\sqrt{1}

STEP 7

Calculate the square root.
f(5)=1f(5)=1

STEP 8

Now, let's find f(x)f(x) for x=3x=3. We substitute x=3x=3 into the function.
f(3)=34f(3)=\sqrt{3-4}

STEP 9

implify the expression inside the square root.
f(3)=f(3)=\sqrt{-}

STEP 10

Since the square root of a negative number is not a real number, we conclude that f(3)f(3) is not a real number.
So, the values of f(x)f(x) for x=4x=4, x=5x=5, and x=3x=3 are0,, and "Not a real number", respectively.

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