Math

QuestionIdentify the cation and anion for each ionic compound: Fe(NO3)2\mathrm{Fe}(\mathrm{NO}_{3})_{2} and Cr(OH)4\mathrm{Cr}(\mathrm{OH})_{4}.

Studdy Solution

STEP 1

Assumptions1. Theionic compound is made up of a cation and an anion. . The cation is the positively charged ion and the anion is the negatively charged ion.
3. The cation is always written first in theionic compound formula.
4. The charge of the cation and anion in the compound must balance each other out.

STEP 2

We need to identify the cation and anion in theionic compound Fe(NO)2\mathrm{Fe}\left(\mathrm{NO}_{}\right)_{2}.

STEP 3

The cation is the first part of the compound, which is Fe\mathrm{Fe} in this case.

STEP 4

Write the symbol for the cation with its charge. The charge of Fe\mathrm{Fe} in this compound is 2+2+, so the cation is Fe2+\mathrm{Fe}^{2+}.

STEP 5

The anion is the second part of the compound, which is NO3\mathrm{NO}_{3} in this case.

STEP 6

Write the symbol for the anion with its charge. The charge of NO3\mathrm{NO}_{3} in this compound is 11-, so the anion is NO3\mathrm{NO}_{3}^{-}.

STEP 7

Now we can complete the table by filling in the symbols for the cation and anion of theionic compound Fe(NO3)2\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}.
\begin{tabular}{|c|c|c|} \hlineionic compound & cation & anion \\ \hline NaCl\mathrm{NaCl} & Na+\mathrm{Na}^{+} & Cl\mathrm{Cl}^{-} \\ \hline Cr(OH)4\mathrm{Cr}(\mathrm{OH})_{4} & Cr4+\mathrm{Cr}^{4+} & OH\mathrm{OH}^{-} \\ \hline VS\mathrm{VS} & V2+\mathrm{V}^{2+} & 2\mathrm{}^{2-} \\ \hline Fe(NO3)2\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2} & Fe2+\mathrm{Fe}^{2+} & NO3\mathrm{NO}_{3}^{-} \\ \hline NH4 \mathrm{NH}_{4} \mathrm{~} & NH4+\mathrm{NH}_{4}^{+} & \mathrm{}^{-} \\ \hline\end{tabular}

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