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QuestionComplete the following acid-base reaction with balanced molecular, total ionic, and net ionic equations. Be sure to include states of matter in your answer. calcium hydroxide (aq)+acetic⁡acid⁡(aq)→(a q)+\operatorname{acetic} \operatorname{acid}(a q) \rightarrow

Studdy Solution

STEP 1

Assumptions
1. Calcium hydroxide is represented by the chemical formula Ca(OH)2 \text{Ca(OH)}_2 .
2. Acetic acid is represented by the chemical formula CH3COOH \text{CH}_3\text{COOH} .
3. The reaction occurs in an aqueous solution.
4. The products of the reaction will include a salt and water.
5. Calcium acetate is the salt formed, represented by Ca(CH3COO)2 \text{Ca(CH}_3\text{COO)}_2 .
6. Water is formed as a result of the neutralization reaction.

STEP 2

Write the balanced molecular equation for the reaction.
The balanced molecular equation for the reaction between calcium hydroxide and acetic acid is:
Ca(OH)2(aq)+2CH3COOH(aq)→Ca(CH3COO)2(aq)+2H2O(l) \text{Ca(OH)}_2(aq) + 2\text{CH}_3\text{COOH}(aq) \rightarrow \text{Ca(CH}_3\text{COO)}_2(aq) + 2\text{H}_2\text{O}(l)

STEP 3

Write the total ionic equation for the reaction.
In the total ionic equation, we separate all strong electrolytes into their constituent ions. Calcium hydroxide and calcium acetate dissociate in water, while acetic acid is a weak acid and does not completely dissociate:
Ca2+(aq)+2OH−(aq)+2CH3COOH(aq)→Ca2+(aq)+2CH3COO−(aq)+2H2O(l) \text{Ca}^{2+}(aq) + 2\text{OH}^-(aq) + 2\text{CH}_3\text{COOH}(aq) \rightarrow \text{Ca}^{2+}(aq) + 2\text{CH}_3\text{COO}^-(aq) + 2\text{H}_2\text{O}(l)

STEP 4

Write the net ionic equation for the reaction.
In the net ionic equation, we eliminate the spectator ions, which are ions that appear on both sides of the equation and do not participate in the reaction. In this case, the calcium ions Ca2+ \text{Ca}^{2+} are spectator ions:
2OH−(aq)+2CH3COOH(aq)→2CH3COO−(aq)+2H2O(l) 2\text{OH}^-(aq) + 2\text{CH}_3\text{COOH}(aq) \rightarrow 2\text{CH}_3\text{COO}^-(aq) + 2\text{H}_2\text{O}(l)

STEP 5

Simplify the net ionic equation by dividing all coefficients by 2:
OH−(aq)+CH3COOH(aq)→CH3COO−(aq)+H2O(l) \text{OH}^-(aq) + \text{CH}_3\text{COOH}(aq) \rightarrow \text{CH}_3\text{COO}^-(aq) + \text{H}_2\text{O}(l)
This is the final net ionic equation for the reaction.

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