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Math  /  Data & Statistics

QuestionClaim: The mean pulse rate (in beats per minute) of adult males is equal to 69.2 bpm . For a random sample of 175 adult males, the mean pulse rate is 69.5 bpm and the standard deviation is 10.8 bpm . Complete parts (a) and (b) below. a. Express the original claim in symbolic form. □\square □\square □\square bpm (Type an integer or a decimal. Do not round.) b. Identify the null and alternative hypotheses. H0\mathrm{H}_{0} : □\square □\square □\square bpm H1\mathrm{H}_{1} : □\square □\square bpm (Type integers or decimals. Do not round.)

Studdy Solution

STEP 1

1. We are dealing with hypothesis testing for the mean pulse rate of adult males.
2. The sample size is 175, which is sufficiently large for the Central Limit Theorem to apply.
3. The population mean pulse rate is claimed to be 69.2 bpm.

STEP 2

1. Express the original claim in symbolic form.
2. Identify the null and alternative hypotheses.

STEP 3

Express the original claim that the mean pulse rate is equal to 69.2 bpm in symbolic form:
μ=69.2 bpm \mu = 69.2 \, \text{bpm}

STEP 4

Identify the null hypothesis (H0H_0) and the alternative hypothesis (H1H_1):
H0:μ=69.2 bpmH_0: \mu = 69.2 \, \text{bpm}
H1:μ≠69.2 bpmH_1: \mu \neq 69.2 \, \text{bpm}
The original claim in symbolic form is:
μ=69.2 bpm \mu = 69.2 \, \text{bpm}
The null and alternative hypotheses are:
H0:μ=69.2 bpm H_0: \mu = 69.2 \, \text{bpm}
H1:μ≠69.2 bpm H_1: \mu \neq 69.2 \, \text{bpm}

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