Math

QuestionChoose the expressions equivalent to 7(3n+5)+47(3 n+5)+4: (3n+5)7+4(3 n+5) 7+4, 21n+3921 n+39, 5(3n+7)+45(3 n+7)+4, 7(5n+3)+47(5 n+3)+4.

Studdy Solution

STEP 1

Assumptions1. We are looking for expressions that are equivalent to 7(3n+5)+47(3 n+5)+4. . Equivalent expressions will have the same value for all values of nn.

STEP 2

We will start by simplifying the given expression 7(n+5)+47( n+5)+4.
To do this, we distribute the 77 across the terms inside the parentheses.
7( n+5)+4 =7 \cdotn +7 \cdot5 +4

STEP 3

Now, perform the multiplication to simplify the expression.
73n+75+=21n+35+7 \cdot3n +7 \cdot5 + =21n +35 +

STEP 4

Combine like terms to further simplify the expression.
21n+35+4=21n+3921n +35 +4 =21n +39

STEP 5

Now, we will compare the simplified expression 21n+3921n +39 with each of the provided expressions to see if they are equivalent.
First, compare with (3n+5)7+4(3 n+5)7+4. This expression is just a rearrangement of the original expression, so it is equivalent.

STEP 6

Next, compare with 21n+3921 n+39. This expression is the same as the simplified expression, so it is equivalent.

STEP 7

Then, compare with 5(3n+7)+45(3 n+7)+4. Distribute the 55 across the terms inside the parentheses.
5(3n+7)+4=53n+57+45(3 n+7)+4 =5 \cdot3n +5 \cdot7 +4

STEP 8

Perform the multiplication to simplify the expression.
53n+57+4=15n+35+45 \cdot3n +5 \cdot7 +4 =15n +35 +4

STEP 9

Combine like terms to further simplify the expression.
15n+35+4=15n+3915n +35 +4 =15n +39This expression is not equivalent to the original expression because the coefficient of nn is different.

STEP 10

Finally, compare with 7(5n+3)+47(5 n+3)+4. Distribute the 77 across the terms inside the parentheses.
7(5n+3)+4=75n+73+47(5 n+3)+4 =7 \cdot5n +7 \cdot3 +4

STEP 11

Perform the multiplication to simplify the expression.
75n+73+4=35n+21+47 \cdot5n +7 \cdot3 +4 =35n +21 +4

STEP 12

Combine like terms to further simplify the expression.
35n+21+4=35n+2535n +21 +4 =35n +25This expression is not equivalent to the original expression because the coefficient of nn is different and the constant term is also different.
The expressions equivalent to 7(n+5)+47( n+5)+4 are (n+5)7+4( n+5)7+4 and 21n+3921 n+39.

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