Math  /  Geometry

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What is the area of rhombus ABCDA B C D ?
Enter your answer in the box. Do not round at any steps. \square units 2^{2}

Studdy Solution

STEP 1

1. The rhombus ABCDABCD is defined by the vertices A(1,0)A(1, 0), B(7,2)B(7, -2), C(1,4)C(1, -4), and D(5,2)D(-5, -2).
2. The diagonals of the rhombus intersect at right angles.
3. The diagonals can be calculated using the distance formula.

STEP 2

1. Calculate the lengths of the diagonals ACAC and BDBD.
2. Use the formula for the area of a rhombus using its diagonals.
3. Calculate the area.

STEP 3

Calculate the length of diagonal ACAC using the distance formula:
The coordinates of AA are (1,0)(1, 0) and CC are (1,4)(1, -4).
AC=(11)2+(0(4))2 AC = \sqrt{(1 - 1)^2 + (0 - (-4))^2} =0+42 = \sqrt{0 + 4^2} =16 = \sqrt{16} =4 = 4

STEP 4

Calculate the length of diagonal BDBD using the distance formula:
The coordinates of BB are (7,2)(7, -2) and DD are (5,2)(-5, -2).
BD=(7(5))2+(2(2))2 BD = \sqrt{(7 - (-5))^2 + (-2 - (-2))^2} =122+0 = \sqrt{12^2 + 0} =144 = \sqrt{144} =12 = 12

STEP 5

Use the formula for the area of a rhombus using its diagonals:
Area=12×AC×BD \text{Area} = \frac{1}{2} \times AC \times BD
Substitute the values:
Area=12×4×12 \text{Area} = \frac{1}{2} \times 4 \times 12

STEP 6

Calculate the area:
Area=12×4×12 \text{Area} = \frac{1}{2} \times 4 \times 12 =2×12 = 2 \times 12 =24 = 24
The area of rhombus ABCDABCD is:
24 units2 \boxed{24} \text{ units}^2

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