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Math

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PROBLEM

Calculate the interior angle sum of an 11-sided polygon using (n2)×180(n-2) \times 180. Round to the nearest tenth.

STEP 1

Assumptions1. The polygon has11 sides. The formula for the interior angle sum of a polygon is (n)×180(n-) \times180 degrees, where nn is the number of sides the polygon has

STEP 2

We need to find the interior angle sum for a polygon with11 sides. We can do this by substituting n=11n =11 into the formula.
Interioranglesum=(n2)×180degreesInterior\, angle\, sum = (n-2) \times180\, degrees

STEP 3

Substitute n=11n =11 into the formula.
Interioranglesum=(112)×180degreesInterior\, angle\, sum = (11-2) \times180\, degrees

STEP 4

Calculate the value inside the parentheses.
Interioranglesum=9×180degreesInterior\, angle\, sum =9 \times180\, degrees

SOLUTION

Calculate the interior angle sum.
Interioranglesum=9×180=1620degreesInterior\, angle\, sum =9 \times180 =1620\, degreesThe interior angle sum for a polygon with11 sides is1620 degrees.

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