Math

QuestionFind the value of [G(1)]3[G(2)]2+4G(1)10\frac{{[G(-1)]^{3} - [G(2)]^{2} + 4 \cdot G(-1)}}{10} given G(1)=20G(-1) = 20 and G(2)=10G(2) = -10.

Studdy Solution

STEP 1

Assumptions1. The function G(x)G(x) is given for two points G(1)=20G(-1) =20 and G()=10G() = -10. . We need to substitute these values into the given expression and simplify.

STEP 2

First, let's substitute the given values of G(1)G(-1) and G(2)G(2) into the expression.[G(1)][G(2)]2+4G(1)10=[20][10]2+42010\frac{{[G(-1)]^{} - [G(2)]^{2} +4 \cdot G(-1)}}{10} = \frac{{[20]^{} - [-10]^{2} +4 \cdot20}}{10}

STEP 3

Now, simplify the numerator of the fraction.203=800020^{3} =8000 102=100-10^{2} =100 20=80 \cdot20 =80
So, the expression becomes8000100+8010\frac{{8000 -100 +80}}{10}

STEP 4

Next, we simplify the numerator by performing the subtraction and addition operations.
8000100+80=79808000 -100 +80 =7980
So, the expression becomes798010\frac{7980}{10}

STEP 5

Finally, we divide the numerator by the denominator to find the value of the expression.
798010=798\frac{7980}{10} =798
So, the value of the given expression is798.

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