QuestionCalculate the energy needed for a 75-watt lightbulb to burn for $3.0 \mathrm{~h}$ in kJ and other units.

Studdy Solution

STEP 1

Assumptions1. The energy required to keep a75-watt lightbulb burning for1.0 h is260 kJ. . We need to find the energy required to keep the same lightbulb burning for3.0 h.
3. The energy consumption is directly proportional to the time the lightbulb is kept on.

STEP 2

First, we need to calculate the total energy required to keep the lightbulb burning for.0 h. We can do this by multiplying the energy required for1.0 h by.0.
$Energy_{h} = Energy_{1h} \times.0$

STEP 3

Now, plug in the given value for the energy required for1.0 h to calculate the energy required for3.0 h.
$Energy_{3h} =260\, kJ \times3.0$

STEP 4

Calculate the total energy required for3.0 h.
$Energy_{3h} =260\, kJ \times3.0 =780\, kJ$ The energy required to keep the lightbulb burning for3.0 h is780 kJ.

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