Math  /  Algebra

Question(12) m3+9nm^{3}+9 n when m=4m=4 and n=5n=5

Studdy Solution

STEP 1

What is this asking? We need to find the value of the expression m3+9nm^3 + 9n when mm is **4** and nn is **5**. Watch out! Don't forget to do the exponent before the multiplication and addition!
Order of operations is key!

STEP 2

1. Substitute the values
2. Calculate the exponent
3. Calculate the multiplication
4. Calculate the sum

STEP 3

Let's **kick things off** by plugging in our given values for mm and nn into our expression!
Remember, mm is **4** and nn is **5**.
So, m3+9nm^3 + 9n becomes (4)3+9(5)(4)^3 + 9 \cdot (5).

STEP 4

Now, let's **tackle that exponent**! 434^3 means 44 multiplied by itself three times: 4444 \cdot 4 \cdot 4.

STEP 5

444 \cdot 4 is **16**.
Then, 16416 \cdot 4 gives us **64**.
So, (4)3(4)^3 is **64**!
Our expression now looks like this: 64+9(5)64 + 9 \cdot (5).

STEP 6

Next up, we'll **conquer the multiplication**!
We have 959 \cdot 5, which equals **45**.
Our expression is now 64+4564 + 45.

STEP 7

Finally, let's **wrap this up** with some addition! 64+4564 + 45 gives us a **grand total of 109**!

STEP 8

So, the value of the expression m3+9nm^3 + 9n when m=4m = 4 and n=5n = 5 is **109**!

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