QuestionSolve for $c$ in the equation $w=\frac{z-c}{r}$ . What is $c$ ?

Studdy Solution

STEP 1

Assumptions1. The given equation is $w=\frac{z-c}{r}$ . . We need to solve this equation for $c$ .

STEP 2

The first step to isolate $c$ is to multiply both sides of the equation by $r$ to get rid of the denominator on the right side.
$r \cdot w = r \cdot \frac{z-c}{r}$

STEP 3

implify the right side of the equation.
$r \cdot w = z - c$

STEP 4

Now, we need to isolate $c$ . We can do this by adding $c$ to both sides of the equation and subtracting $r \cdot w$ from both sides of the equation.
$c + r \cdot w = z$

STEP 5

Finally, to isolate $c$ , we can rewrite the equation as $c = z - r \cdot w$ So, the solution is $c = z - r \cdot w$ .

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QuestionSolve for $c$ in the equation $w=\frac{z-c}{r}$ . What is $c$ ?

Studdy Solution

STEP 1

Assumptions1. The given equation is $w=\frac{z-c}{r}$ . . We need to solve this equation for $c$ .

STEP 2

The first step to isolate $c$ is to multiply both sides of the equation by $r$ to get rid of the denominator on the right side.
$r \cdot w = r \cdot \frac{z-c}{r}$

STEP 3

implify the right side of the equation.
$r \cdot w = z - c$

STEP 4

Now, we need to isolate $c$ . We can do this by adding $c$ to both sides of the equation and subtracting $r \cdot w$ from both sides of the equation.
$c + r \cdot w = z$

STEP 5

Finally, to isolate $c$ , we can rewrite the equation as $c = z - r \cdot w$ So, the solution is $c = z - r \cdot w$ .

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QuestionSolve for ccc in the equation w=z−crw=\frac{z-c}{r}w=rz−c​. What is ccc?

Studdy Solution

STEP 1

Assumptions1. The given equation is w=z−crw=\frac{z-c}{r}w=rz−c​. . We need to solve this equation for ccc.

STEP 2

The first step to isolate ccc is to multiply both sides of the equation by rrr to get rid of the denominator on the right side.r⋅w=r⋅z−crr \cdot w = r \cdot \frac{z-c}{r}r⋅w=r⋅rz−c​

STEP 3

implify the right side of the equation.r⋅w=z−cr \cdot w = z - cr⋅w=z−c

STEP 4

Now, we need to isolate ccc. We can do this by adding ccc to both sides of the equation and subtracting r⋅wr \cdot wr⋅w from both sides of the equation.c+r⋅w=zc + r \cdot w = zc+r⋅w=z

STEP 5

Finally, to isolate ccc, we can rewrite the equation asc=z−r⋅wc = z - r \cdot wc=z−r⋅wSo, the solution is c=z−r⋅wc = z - r \cdot wc=z−r⋅w.

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QuestionSolve for $c$ in the equation $w=\frac{z-c}{r}$ . What is $c$ ?

Assumptions1. The given equation is $w=\frac{z-c}{r}$ . . We need to solve this equation for $c$ .

The first step to isolate $c$ is to multiply both sides of the equation by $r$ to get rid of the denominator on the right side.
$r \cdot w = r \cdot \frac{z-c}{r}$

implify the right side of the equation.
$r \cdot w = z - c$

Now, we need to isolate $c$ . We can do this by adding $c$ to both sides of the equation and subtracting $r \cdot w$ from both sides of the equation.
$c + r \cdot w = z$

Finally, to isolate $c$ , we can rewrite the equation as $c = z - r \cdot w$ So, the solution is $c = z - r \cdot w$ .