Math  /  Calculus

QuestionC) Calculate L3L_{3} and R3R_{3} for f(x)=12xf(x)=\frac{12}{x} on [2,5][2,5]

Studdy Solution

STEP 1

1. We are given the function f(x)=12x f(x) = \frac{12}{x} .
2. We need to calculate the left Riemann sum L3 L_3 and the right Riemann sum R3 R_3 over the interval [2,5][2, 5].
3. The interval [2,5][2, 5] is divided into 3 equal subintervals.

STEP 2

1. Determine the width of each subinterval.
2. Calculate the left Riemann sum L3 L_3 .
3. Calculate the right Riemann sum R3 R_3 .

STEP 3

Determine the width of each subinterval:
The interval [2,5][2, 5] is divided into 3 equal subintervals. The width Δx\Delta x of each subinterval is given by:
Δx=523=1\Delta x = \frac{5 - 2}{3} = 1

STEP 4

Calculate the left Riemann sum L3 L_3 :
The left endpoints of the subintervals are x0=2 x_0 = 2 , x1=3 x_1 = 3 , and x2=4 x_2 = 4 .
\[ L_3 = \Delta x \left[ f(x_0) + f(x_1) + f(x_2) \right] $
Substitute the function values:
L3=1[122+123+124]L_3 = 1 \left[ \frac{12}{2} + \frac{12}{3} + \frac{12}{4} \right]
Simplify:
L3=1[6+4+3]=13L_3 = 1 \left[ 6 + 4 + 3 \right] = 13

STEP 5

Calculate the right Riemann sum R3 R_3 :
The right endpoints of the subintervals are x1=3 x_1 = 3 , x2=4 x_2 = 4 , and x3=5 x_3 = 5 .
\[ R_3 = \Delta x \left[ f(x_1) + f(x_2) + f(x_3) \right] $
Substitute the function values:
R3=1[123+124+125]R_3 = 1 \left[ \frac{12}{3} + \frac{12}{4} + \frac{12}{5} \right]
Simplify:
R3=1[4+3+2.4]=9.4R_3 = 1 \left[ 4 + 3 + 2.4 \right] = 9.4
The values of L3 L_3 and R3 R_3 are:
L3=13 L_3 = 13 R3=9.4 R_3 = 9.4

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