QuestionBelow is a hypothesis test. Label the different parts of the test in the boxes.
A hospital director is told that $47 \%$ of the treated patients are uninsured. The director wants to test the claim that the percentage of uninsured patients is over the expected percentage. A sample of 400 patients is found that 200 were uninsured. At the 0.02 level, is there enough evidence to support the director's claim? $$\begin{array}{l} H_{o}: p \leq 0.47 \\ H_{a}: p>0.47 \end{array}$$ $$Z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.5-0.47}{\sqrt{\frac{0.47(1-0.47)}{400}}}=\frac{0.03}{\sqrt{\frac{0.47(0.53)}{400}}}=\frac{0.03}{\sqrt{\frac{0.2491}{400}}}=\frac{0.03}{\sqrt{0.00062275}}=\frac{0.03}{0.02495}=1.20$$