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Math

QuestionBài 1: Tìm số tự nhiên xx sao cho xx chia hết cho 1515, 3030, 4545 và 50<x<14050 < x < 140.
Bài 2: Tìm số tự nhiên x\mathrm{x} sao cho 88:x88: \mathrm{x}, 40:x40: \mathrm{x}, 56:x56: \mathrm{x} và x≥4\mathrm{x} \geq 4.

Studdy Solution

STEP 1

Assumptions1. We are looking for a natural number xx. . The number xx must be a divisor of15,30, and45 for the first problem.
3. The number xx must be a divisor of88,40, and56 for the second problem.
4. For the first problem, xx must be greater than50 and less than140.
5. For the second problem, xx must be greater than or equal to4.

STEP 2

For the first problem, we need to find the common divisors of15,30, and45. We can do this by listing out the divisors of each number and finding the common ones.

STEP 3

The divisors of15 are1,3,5, and15.

STEP 4

The divisors of30 are1,2,3,,6,10,15, and30.

STEP 5

The divisors of45 are1,3,5,9,15, and45.

STEP 6

The common divisors of15,30, and45 are1,3,5, and15.

STEP 7

From these common divisors, we need to find the ones that are greater than50 and less than140. However, none of the common divisors are within this range, so there are no solutions for the first problem.

STEP 8

For the second problem, we need to find the common divisors of88,40, and56. We can do this by listing out the divisors of each number and finding the common ones.

STEP 9

The divisors of88 are,2,4,8,11,22,44, and88.

STEP 10

The divisors of40 are,2,4,5,8,10,20, and40.

STEP 11

The divisors of56 are,,4,7,8,14,28, and56.

STEP 12

The common divisors of88,40, and56 are,2,4, and8.

STEP 13

From these common divisors, we need to find the ones that are greater than or equal to. The solutions for the second problem are and8.

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