QuestionSolve for $x$ : $x \cdot \frac{1}{11} = 1$ and $1 \div \frac{1}{5} = x$ .

Studdy Solution

STEP 1

Assumptions1. We are solving for the variable $x$ in both equations. . The operations of multiplication and division are defined and valid in these equations.

STEP 2

For equation b, we need to isolate $x$ . We can do this by multiplying both sides of the equation by11.
$x \cdot \frac{1}{11} \times11 =1 \times1 \times11$

STEP 3

implify the equation to solve for $x$ .
$x =1 \times1 \times11$

STEP 4

Calculate the value of $x$ .
$x =1 \times1 \times11 =11$

STEP 5

For equation c, we need to isolate $x$ . We can do this by dividing both sides of the equation by5.
$\frac{1}{\frac{1}{5}} \div5 = x$

STEP 6

implify the left side of the equation.
$\frac{1}{\frac{1}{5}} =5$ So the equation becomes $5 \div5 = x$

STEP 7

Calculate the value of $x$ .
$x =5 \div5 =1$ So, for equation b, $x =11$ and for equation c, $x =1$ .

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QuestionSolve for $x$ : $x \cdot \frac{1}{11} = 1$ and $1 \div \frac{1}{5} = x$ .

Studdy Solution

STEP 1

Assumptions1. We are solving for the variable $x$ in both equations. . The operations of multiplication and division are defined and valid in these equations.

STEP 2

For equation b, we need to isolate $x$ . We can do this by multiplying both sides of the equation by11.
$x \cdot \frac{1}{11} \times11 =1 \times1 \times11$

STEP 3

implify the equation to solve for $x$ .
$x =1 \times1 \times11$

STEP 4

Calculate the value of $x$ .
$x =1 \times1 \times11 =11$

STEP 5

For equation c, we need to isolate $x$ . We can do this by dividing both sides of the equation by5.
$\frac{1}{\frac{1}{5}} \div5 = x$

STEP 6

implify the left side of the equation.
$\frac{1}{\frac{1}{5}} =5$ So the equation becomes $5 \div5 = x$

STEP 7

Calculate the value of $x$ .
$x =5 \div5 =1$ So, for equation b, $x =11$ and for equation c, $x =1$ .

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QuestionSolve for xxx: x⋅111=1x \cdot \frac{1}{11} = 1x⋅111​=1 and 1÷15=x1 \div \frac{1}{5} = x1÷51​=x.

Studdy Solution

STEP 1

Assumptions1. We are solving for the variable xxx in both equations. . The operations of multiplication and division are defined and valid in these equations.

STEP 2

For equation b, we need to isolate xxx. We can do this by multiplying both sides of the equation by11.x⋅111×11=1×1×11x \cdot \frac{1}{11} \times11 =1 \times1 \times11x⋅111​×11=1×1×11

STEP 3

implify the equation to solve for xxx.x=1×1×11x =1 \times1 \times11x=1×1×11

STEP 4

Calculate the value of xxx.x=1×1×11=11x =1 \times1 \times11 =11x=1×1×11=11

STEP 5

For equation c, we need to isolate xxx. We can do this by dividing both sides of the equation by5.115÷5=x\frac{1}{\frac{1}{5}} \div5 = x51​1​÷5=x

STEP 6

implify the left side of the equation.115=5\frac{1}{\frac{1}{5}} =551​1​=5So the equation becomes5÷5=x5 \div5 = x5÷5=x

STEP 7

Calculate the value of xxx.x=5÷5=1x =5 \div5 =1x=5÷5=1So, for equation b, x=11x =11x=11 and for equation c, x=1x =1x=1.

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QuestionSolve for $x$ : $x \cdot \frac{1}{11} = 1$ and $1 \div \frac{1}{5} = x$ .

Assumptions1. We are solving for the variable $x$ in both equations. . The operations of multiplication and division are defined and valid in these equations.

For equation b, we need to isolate $x$ . We can do this by multiplying both sides of the equation by11.
$x \cdot \frac{1}{11} \times11 =1 \times1 \times11$

implify the equation to solve for $x$ .
$x =1 \times1 \times11$

Calculate the value of $x$ .
$x =1 \times1 \times11 =11$

For equation c, we need to isolate $x$ . We can do this by dividing both sides of the equation by5.
$\frac{1}{\frac{1}{5}} \div5 = x$

implify the left side of the equation.
$\frac{1}{\frac{1}{5}} =5$ So the equation becomes $5 \div5 = x$

Calculate the value of $x$ .
$x =5 \div5 =1$ So, for equation b, $x =11$ and for equation c, $x =1$ .