QuestionAva swims 70 yards in 2 minutes. How far can she swim in 5 minutes? Calculate: $d = \frac{70 \text{ yards}}{2 \text{ min}} \times 5 \text{ min}$ .

Studdy Solution

STEP 1

Assumptions1. Ava swims at a constant rate. . She swims70 yards in minutes.

STEP 2

First, we need to find the rate at which Ava swims. We can do this by dividing the distance she swims by the time it takes.
$Rate = \frac{Distance}{Time}$

STEP 3

Now, plug in the given values for the distance and time to calculate the rate.
$Rate = \frac{70\, yards}{2\, minutes}$

STEP 4

Calculate the rate at which Ava swims.
$Rate = \frac{70\, yards}{2\, minutes} =35\, yards/minute$

STEP 5

Now that we have the rate at which Ava swims, we can find the distance she would swim in5 minutes. We can do this by multiplying the rate by the time.
$Distance = Rate \times Time$

STEP 6

Plug in the values for the rate and the time to calculate the distance.
$Distance =35\, yards/minute \times5\, minutes$

STEP 7

Calculate the distance Ava would swim in5 minutes.
$Distance =35\, yards/minute \times5\, minutes =175\, yards$ You would expect Ava to swim175 yards in5 minutes.

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QuestionAva swims 70 yards in 2 minutes. How far can she swim in 5 minutes? Calculate: $d = \frac{70 \text{ yards}}{2 \text{ min}} \times 5 \text{ min}$ .

Studdy Solution

STEP 1

Assumptions1. Ava swims at a constant rate. . She swims70 yards in minutes.

STEP 2

First, we need to find the rate at which Ava swims. We can do this by dividing the distance she swims by the time it takes.
$Rate = \frac{Distance}{Time}$

STEP 3

Now, plug in the given values for the distance and time to calculate the rate.
$Rate = \frac{70\, yards}{2\, minutes}$

STEP 4

Calculate the rate at which Ava swims.
$Rate = \frac{70\, yards}{2\, minutes} =35\, yards/minute$

STEP 5

Now that we have the rate at which Ava swims, we can find the distance she would swim in5 minutes. We can do this by multiplying the rate by the time.
$Distance = Rate \times Time$

STEP 6

Plug in the values for the rate and the time to calculate the distance.
$Distance =35\, yards/minute \times5\, minutes$

STEP 7

Calculate the distance Ava would swim in5 minutes.
$Distance =35\, yards/minute \times5\, minutes =175\, yards$ You would expect Ava to swim175 yards in5 minutes.

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QuestionAva swims 70 yards in 2 minutes. How far can she swim in 5 minutes? Calculate: d=70 yards2 min×5 mind = \frac{70 \text{ yards}}{2 \text{ min}} \times 5 \text{ min}d=2 min70 yards​×5 min.

Studdy Solution

STEP 1

Assumptions1. Ava swims at a constant rate. . She swims70 yards in minutes.

STEP 2

First, we need to find the rate at which Ava swims. We can do this by dividing the distance she swims by the time it takes.Rate=DistanceTimeRate = \frac{Distance}{Time}Rate=TimeDistance​

STEP 3

Now, plug in the given values for the distance and time to calculate the rate.Rate=70 yards2 minutesRate = \frac{70\, yards}{2\, minutes}Rate=2minutes70yards​

STEP 4

Calculate the rate at which Ava swims.Rate=70 yards2 minutes=35 yards/minuteRate = \frac{70\, yards}{2\, minutes} =35\, yards/minuteRate=2minutes70yards​=35yards/minute

STEP 5

Now that we have the rate at which Ava swims, we can find the distance she would swim in5 minutes. We can do this by multiplying the rate by the time.Distance=Rate×TimeDistance = Rate \times TimeDistance=Rate×Time

STEP 6

Plug in the values for the rate and the time to calculate the distance.Distance=35 yards/minute×5 minutesDistance =35\, yards/minute \times5\, minutesDistance=35yards/minute×5minutes

STEP 7

Calculate the distance Ava would swim in5 minutes.Distance=35 yards/minute×5 minutes=175 yardsDistance =35\, yards/minute \times5\, minutes =175\, yardsDistance=35yards/minute×5minutes=175yardsYou would expect Ava to swim175 yards in5 minutes.

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionAva swims 70 yards in 2 minutes. How far can she swim in 5 minutes? Calculate: $d = \frac{70 \text{ yards}}{2 \text{ min}} \times 5 \text{ min}$ .

First, we need to find the rate at which Ava swims. We can do this by dividing the distance she swims by the time it takes.
$Rate = \frac{Distance}{Time}$

Now, plug in the given values for the distance and time to calculate the rate.
$Rate = \frac{70\, yards}{2\, minutes}$

Calculate the rate at which Ava swims.
$Rate = \frac{70\, yards}{2\, minutes} =35\, yards/minute$

Now that we have the rate at which Ava swims, we can find the distance she would swim in5 minutes. We can do this by multiplying the rate by the time.
$Distance = Rate \times Time$

Plug in the values for the rate and the time to calculate the distance.
$Distance =35\, yards/minute \times5\, minutes$

Calculate the distance Ava would swim in5 minutes.
$Distance =35\, yards/minute \times5\, minutes =175\, yards$ You would expect Ava to swim175 yards in5 minutes.