Math

QuestionGiven frequency distributions for XX and YY, create histograms, find relative frequencies, and compare averages.

Studdy Solution

STEP 1

Assumptions1. The frequency distribution of XX and YY is given in the table. . The values of XX and YY are discrete.
3. The frequencies are absolute, not relative.

STEP 2

To draw a histogram of frequencies for XX, we need to represent the values of XX on the x-axis and their corresponding frequencies on the y-axis.

STEP 3

Similarly, to draw a histogram of relative frequencies for YY, we first need to calculate the relative frequencies. The relative frequency of a value is the absolute frequency of that value divided by the total frequency.
RelativeFrequencyofY=FrequencyofYTotalFrequencyofYRelative\, Frequency\, of\, Y = \frac{Frequency\, of\, Y}{Total\, Frequency\, of\, Y}

STEP 4

To find the relative frequencies for XX, we apply the same formula as in3, but for XX.
RelativeFrequencyofX=FrequencyofXTotalFrequencyofXRelative\, Frequency\, of\, X = \frac{Frequency\, of\, X}{Total\, Frequency\, of\, X}

STEP 5

To find the percentage that XX is at least2, we need to sum the frequencies of XX for values2,3, and4, and then divide by the total frequency of XX, and multiply by100 to convert to a percentage.
PercentagethatXisatleast2=FrequencyofXforvalues2,3,and4TotalFrequencyofX×100Percentage\, that\, X\, is\, at\, least\,2 = \frac{Frequency\, of\, X\, for\, values\,2,\,3,\, and\,4}{Total\, Frequency\, of\, X} \times100

STEP 6

To find the percentage that Y=2Y=2, we divide the frequency of YY for value2 by the total frequency of YY, and multiply by100 to convert to a percentage.
PercentagethatY=2=FrequencyofYforvalue2TotalFrequencyofY×100Percentage\, that\, Y=2 = \frac{Frequency\, of\, Y\, for\, value\,2}{Total\, Frequency\, of\, Y} \times100

STEP 7

To find which variable, XX or YY, has a higher average value, we calculate the average (mean) of each variable. The mean of a variable is the sum of the product of each value and its frequency, divided by the total frequency.
MeanofX=(ValueofX×FrequencyofX)TotalFrequencyofXMean\, of\, X = \frac{\sum (Value\, of\, X \times Frequency\, of\, X)}{Total\, Frequency\, of\, X}MeanofY=(ValueofY×FrequencyofY)TotalFrequencyofYMean\, of\, Y = \frac{\sum (Value\, of\, Y \times Frequency\, of\, Y)}{Total\, Frequency\, of\, Y}Then we compare the means of XX and YY to see which is higher.

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