Math

QuestionAnalyze the polynomial h(x)=x63x517x3h(x)=x^{6}-3x^{5}-17x^{3} and determine its end behavior.

Studdy Solution

STEP 1

Assumptions1. The function is a polynomial function of degree6. . The leading coefficient of the polynomial is1.

STEP 2

The end behavior of a polynomial function can be determined by looking at the degree and the leading coefficient of the polynomial.

STEP 3

The degree of the polynomial h(x)=x63x517x3h(x) = x^{6} -3x^{5} -17x^{3} is6, which is an even number.

STEP 4

The leading coefficient of the polynomial h(x)h(x) is1, which is positive.

STEP 5

For a polynomial with an even degree and a positive leading coefficient, as xx approaches positive or negative infinity, h(x)h(x) will approach positive infinity.
limxh(x)=\lim{{x \to \infty}} h(x) = \inftylimxh(x)=\lim{{x \to -\infty}} h(x) = \inftyThis means that the ends of the graph of h(x)h(x) will point upwards.

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