QuestionA worker applies a force of $360 \mathrm{~N}[E]$ on a trunk of mass 50 kg . Frictionol resistance amounts to 340 N . What is the acceleration of the trunk?

Studdy Solution

STEP 1

1. The worker applies a force of $360 \, \mathrm{N}$ in the east direction on the trunk.
2. The mass of the trunk is $50 \, \mathrm{kg}$ .
3. The frictional resistance opposing the motion is $340 \, \mathrm{N}$ .
4. We are trying to find the acceleration of the trunk.

STEP 2

1. Calculate the net force acting on the trunk.
2. Use Newton's second law to find the acceleration.

STEP 3

Calculate the net force acting on the trunk.
The net force $F_{\text{net}}$ is the applied force minus the frictional force:
$F_{\text{net}} = 360 \, \mathrm{N} - 340 \, \mathrm{N}$
$F_{\text{net}} = 20 \, \mathrm{N}$

STEP 4

Use Newton's second law to find the acceleration.
Newton's second law states that $F = ma$ , where $F$ is the net force, $m$ is the mass, and $a$ is the acceleration.
Rearrange the equation to solve for acceleration $a$ :
$a = \frac{F_{\text{net}}}{m}$
Substitute the known values:
$a = \frac{20 \, \mathrm{N}}{50 \, \mathrm{kg}}$
$a = 0.4 \, \mathrm{m/s^2}$
The acceleration of the trunk is:
$\boxed{0.4 \, \mathrm{m/s^2}}$

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