Math

QuestionFind the height of a triangular park with a base of 200yd200 \mathrm{yd} and an area of 7500yd27500 \mathrm{yd}^{2}.

Studdy Solution

STEP 1

Assumptions1. The park is in the shape of a triangle. The length of the base of the triangle is200 yd3. The area of the triangle is7500 yd²4. We need to find the length of the height of the triangle

STEP 2

The area of a triangle is given by the formulaArea=12×Base×HeightArea = \frac{1}{2} \times Base \times Height

STEP 3

We can rearrange this formula to solve for the heightHeight=2×AreaBaseHeight = \frac{2 \times Area}{Base}

STEP 4

Now, plug in the given values for the base and the area to calculate the height.
Height=2×7500yd2200ydHeight = \frac{2 \times7500\, yd^{2}}{200\, yd}

STEP 5

Perform the multiplication in the numeratorHeight=15000yd2200ydHeight = \frac{15000\, yd^{2}}{200\, yd}

STEP 6

Perform the division to find the heightHeight=15000yd2200yd=75ydHeight = \frac{15000\, yd^{2}}{200\, yd} =75\, ydThe length of the side of the park that forms the height of the triangle is75 yards.

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