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Math  /  Numbers & Operations

QuestionA swimming pool has a volume of 213yd3213 \mathrm{yd}^{3}. Use the table of conversion facts to find out how many gallons of water it would take to completely fill the swimming pool.
Round your answer to two decimal places. □\square gal
Conversion facts for volume and capacity 1 cubic yard (yd3)≈201.97\left(\mathrm{yd}^{3}\right) \approx 201.97 gallons (gal) 1 cubic foot (ft3)≈7.48\left(\mathrm{ft}^{3}\right) \approx 7.48 gallons ( gal) 231 cubic inches (\left(\right. in 3)=1\left.^{3}\right)=1 gallon (gal) Note that ≈\approx means "is approximately equal to". For this problem, treat ≈\approx as if it were ==.

Studdy Solution

STEP 1

1. The volume of the swimming pool is 213 yd3 213 \, \mathrm{yd}^3 .
2. The conversion factor from cubic yards to gallons is 1 yd3=201.97 gallons 1 \, \mathrm{yd}^3 = 201.97 \, \text{gallons} .
3. The goal is to find the total number of gallons needed to fill the pool and round the answer to two decimal places.

STEP 2

1. Identify the conversion factor.
2. Set up the multiplication for conversion.
3. Calculate the total gallons.
4. Round the result to two decimal places.

STEP 3

Identify the conversion factor from cubic yards to gallons:
1 yd3=201.97 gallons 1 \, \mathrm{yd}^3 = 201.97 \, \text{gallons}

STEP 4

Set up the multiplication to convert the volume of the pool from cubic yards to gallons:
213 yd3×201.97 gallons/yd3 213 \, \mathrm{yd}^3 \times 201.97 \, \text{gallons/yd}^3

STEP 5

Perform the multiplication to find the total gallons:
213×201.97=43019.61 213 \times 201.97 = 43019.61

STEP 6

Round the result to two decimal places:
The total number of gallons needed is approximately:
43019.61 gallons \boxed{43019.61 \, \text{gallons}}

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