Math  /  Numbers & Operations

QuestionA store selling school supplies advertises a bundle deal. The consumer can pick a backpack, a binder, a pack of pencils, and notebook paper for a set price. There are 5 types of backpacks, 5 types of binders, 3 types of pencils, and 2 types of notebook paper. How many outcomes are possible in this bundle? A. 140 B. 25 C. 15 D. 150

Studdy Solution

STEP 1

What is this asking? How many different combinations of school supplies can a student make, given the number of choices for each item? Watch out! Don't add the number of choices, we need to multiply them to get the total number of combinations!

STEP 2

1. Set up the calculation
2. Calculate the result

STEP 3

Alright students, let's break this problem down!
We're building a bundle of school supplies, and we need to figure out how many different bundles are possible.
We've got a few different types of each item, so let's think about how to combine them.

STEP 4

We've got 55 choices for backpacks, 55 choices for binders, 33 choices for pencils, and 22 choices for notebook paper.
To find the **total number of combinations**, we **multiply** the number of choices for each item together.
This is because each backpack can be paired with each binder, and each of *those* combinations can be paired with each type of pencil, and so on.
It's a chain reaction of choices!

STEP 5

So, our calculation will look like this: 55325 \cdot 5 \cdot 3 \cdot 2.
This represents all the possible combinations of school supplies.

STEP 6

Let's **calculate** the result!
First, we multiply the number of backpack choices by the number of binder choices: 55=255 \cdot 5 = 25.
So, there are **2525 combinations** of backpacks and binders.

STEP 7

Next, we multiply this result by the number of pencil choices: 253=7525 \cdot 3 = 75.
Now we're up to **7575 combinations** of backpacks, binders, *and* pencils.

STEP 8

Finally, we multiply by the number of notebook paper choices: 752=15075 \cdot 2 = 150.
This gives us a grand total of **150150 possible combinations**!

STEP 9

There are 150150 possible outcomes, so the answer is D.

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