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Math

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PROBLEM

Calculate the income tax h(x)h(x) for a single person given the rules. Find h(1260)h(1260), h(7160)h(7160), and h(49070)h(49070). Round h(49070)h(49070) to the nearest cent.

STEP 1

Assumptions1. The income tax function h(x)h(x) is given by the piecewise function$$h(x)=\left\{\begin{array}{ll} 0.02 x, & \text { if }0 \leq x<6000 \\ 120+0.03(x-6000), & \text { if }6000 \leq x<11,000 \\ 270+0.04(x-11,000), & \text { if } x \geq11,000\end{array}\right.
$$. We are asked to find the values of $h(1260)$, $h(7160)$, and $h(49,070)$.
3. The taxable income is a non-negative real number.

STEP 2

First, let's find the value of h(1260)h(1260). Since 12601260 is between 00 and 60006000, we use the first rule of the piecewise function.
h(1260)=0.02×1260h(1260) =0.02 \times1260

STEP 3

Calculate the value of h(1260)h(1260).
h(1260) =0.02 \times1260 = \($\)25.20

STEP 4

Now, let's find the value of h(7160)h(7160). Since 71607160 is between 60006000 and 1100011000, we use the second rule of the piecewise function.
h(7160)=120+0.03×(71606000)h(7160) =120 +0.03 \times (7160 -6000)

STEP 5

Calculate the value of h(7160)h(7160).
h(7160) =120 +0.03 \times (7160 -6000) =120 +0.03 \times1160 = \($\)174.80

STEP 6

Finally, let's find the value of h(49,070)h(49,070). Since 49,07049,070 is greater than 1100011000, we use the third rule of the piecewise function.
h(49,070)=270+0.04×(49,07011,000)h(49,070) =270 +0.04 \times (49,070 -11,000)

SOLUTION

Calculate the value of h(49,070)h(49,070).
h(49,070) =270 +0.04 \times (49,070 -11,000) =270 +0.04 \times38,070 = \($\)1,792.80Interpretationh(1260)h(1260) means that a single person with a taxable income of 12601260 will pay $25.20 in state income tax.
h(7160)h(7160) means that a single person with a taxable income of 71607160 will pay $174.80 in state income tax.
h(49,070)h(49,070) means that a single person with a taxable income of 49,07049,070 will pay $1,792.80 in state income tax.

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