QuestionFind the $z$ -score for a value of 99 in a normal distribution with mean 92 and standard deviation 6. Round to two decimals.

Studdy Solution

STEP 1

Assumptions1. The mean of the normal distribution is92. The standard deviation of the normal distribution is63. The data value for which we need to find the z-score is99

STEP 2

The formula to calculate a z-score is $z = \frac{X - \mu}{\sigma}$ where- $X$ is the data value- $\mu$ is the mean of the distribution- $\sigma$ is the standard deviation of the distribution

STEP 3

Now, plug in the given values for $X$ , $\mu$ , and $\sigma$ to calculate the z-score.
$z = \frac{99 -92}{6}$

STEP 4

Perform the subtraction in the numerator.
$z = \frac{7}{6}$

STEP 5

Calculate the z-score.
$z = \frac{7}{} =1.17$ The z-score for a data value of99 is1.17.

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QuestionFind the $z$ -score for a value of 99 in a normal distribution with mean 92 and standard deviation 6. Round to two decimals.

Studdy Solution

STEP 1

Assumptions1. The mean of the normal distribution is92. The standard deviation of the normal distribution is63. The data value for which we need to find the z-score is99

STEP 2

The formula to calculate a z-score is $z = \frac{X - \mu}{\sigma}$ where- $X$ is the data value- $\mu$ is the mean of the distribution- $\sigma$ is the standard deviation of the distribution

STEP 3

Now, plug in the given values for $X$ , $\mu$ , and $\sigma$ to calculate the z-score.
$z = \frac{99 -92}{6}$

STEP 4

Perform the subtraction in the numerator.
$z = \frac{7}{6}$

STEP 5

Calculate the z-score.
$z = \frac{7}{} =1.17$ The z-score for a data value of99 is1.17.

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QuestionFind the zzz-score for a value of 99 in a normal distribution with mean 92 and standard deviation 6. Round to two decimals.

Studdy Solution

STEP 1

Assumptions1. The mean of the normal distribution is92. The standard deviation of the normal distribution is63. The data value for which we need to find the z-score is99

STEP 2

The formula to calculate a z-score isz=X−μσz = \frac{X - \mu}{\sigma}z=σX−μ​where- XXX is the data value- μ\muμ is the mean of the distribution- σ\sigmaσ is the standard deviation of the distribution

STEP 3

Now, plug in the given values for XXX, μ\muμ, and σ\sigmaσ to calculate the z-score.z=99−926z = \frac{99 -92}{6}z=699−92​

STEP 4

Perform the subtraction in the numerator.z=76z = \frac{7}{6}z=67​

STEP 5

Calculate the z-score.z=7=1.17z = \frac{7}{} =1.17z=7​=1.17The z-score for a data value of99 is1.17.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionFind the $z$ -score for a value of 99 in a normal distribution with mean 92 and standard deviation 6. Round to two decimals.

The formula to calculate a z-score is $z = \frac{X - \mu}{\sigma}$ where- $X$ is the data value- $\mu$ is the mean of the distribution- $\sigma$ is the standard deviation of the distribution

Now, plug in the given values for $X$ , $\mu$ , and $\sigma$ to calculate the z-score.
$z = \frac{99 -92}{6}$

Perform the subtraction in the numerator.
$z = \frac{7}{6}$

Calculate the z-score.
$z = \frac{7}{} =1.17$ The z-score for a data value of99 is1.17.