Math

QuestionA molecule with two lone pairs and two bonding groups would form what type of molecular geometry? Bent/Angular Linear Tetrahedral Trigonal Planar

Studdy Solution

STEP 1

1. The molecule has two lone pairs and two bonding groups.
2. We need to determine the molecular geometry based on the VSEPR (Valence Shell Electron Pair Repulsion) theory.

STEP 2

1. Understand the basic principles of VSEPR theory.
2. Determine the electron geometry.
3. Identify the molecular geometry based on lone pairs and bonding groups.

STEP 3

According to VSEPR theory, the shape of a molecule is determined by the repulsion between electron pairs (bonding and lone pairs) around the central atom.

STEP 4

Consider the total number of electron pairs (lone pairs + bonding pairs) around the central atom. In this case, there are 4 electron pairs (2 lone pairs and 2 bonding pairs).

STEP 5

The electron geometry for 4 electron pairs is tetrahedral.

STEP 6

To find the molecular geometry, consider only the positions of the atoms (ignore lone pairs). With 2 lone pairs and 2 bonding pairs, the molecular geometry is bent/angular.
The molecular geometry of a molecule with two lone pairs and two bonding groups is:
Bent/Angular \boxed{\text{Bent/Angular}}

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