Math  /  Algebra

Question\qquad A. Magnetic field has only magnitude. B. Magnetic field BB is inversely proportional to the distance rr. C. The force is repulsive if the current carrying wires are parallel. D. The force is attractive if the currents carrying wires are anti parallel.
10. An electric heater is constructed by applying potential difference of 120 V to Nichrome wire has a total resistance of 80Ω80 \Omega. What is the power raiting of the heater? A. 15 W B. 1.8×103 W1.8 \times 10^{3} \mathrm{~W} C. 280 W D. 1.5×103 W1.5 \times 10^{3} \mathrm{~W} \qquad
11. Which of the following is correct statement, when the direction of current is upward? A. the magnetic field is clockwise A. Which C. The magnetic force is into the page - 9. B. the magnetic field is anti clockwise D. all \qquad B. the magnetic field is and intersed in a vessel containing melting indium, 50Ω50 \Omega at 20C20^{\circ} \mathrm{C}. When immersed its resistance increases to 76.8Ω76.8 \Omega. What is the melting point of the indium? (Use α=3.92×103C1\alpha=3.92 \times 10^{-3} \mathrm{C}^{-1} ) D. 1×1040C1 \times 10^{40} \mathrm{C}

Studdy Solution

STEP 1

1. The electric heater operates under Ohm's Law, which relates voltage (V), current (I), and resistance (R) by V=IR V = IR .
2. The power rating (P) of the heater can be calculated using the formula P=V2/R P = V^2 / R .

STEP 2

1. Identify the given values for voltage (V) and resistance (R).
2. Use the power formula to calculate the power rating (P) of the heater.

STEP 3

Identify the given values: - Voltage, V=120V V = 120 \, \text{V} - Resistance, R=80Ω R = 80 \, \Omega

STEP 4

Use the power formula P=V2R P = \frac{V^2}{R} to calculate the power rating of the heater.
P=(120V)280Ω P = \frac{(120 \, \text{V})^2}{80 \, \Omega}

STEP 5

Calculate the numerator:
(120V)2=14400V2 (120 \, \text{V})^2 = 14400 \, \text{V}^2

STEP 6

Divide the result by the resistance:
P=14400V280Ω P = \frac{14400 \, \text{V}^2}{80 \, \Omega}

STEP 7

Perform the division:
P=180W P = 180 \, \text{W}
Solution: The power rating of the heater is 180W 180 \, \text{W} .

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord