QuestionFind the equation of a line with slope 6 that passes through the point $(6,8)$ in point-slope form.

Studdy Solution

STEP 1

Assumptions1. The slope of the line is6. The line passes through the point (6,8)
3. We need to find the equation of the line in point-slope form4. The point-slope form of a line is given by $y - y1 = m(x - x1)$ , where $(x1, y1)$ is a point on the line and $m$ is the slope of the line

STEP 2

The point-slope form of a line is given by $y - y1 = m(x - x1)$ . We can substitute the given slope and point into this formula to find the equation of the line.
$y - y1 = m(x - x1)$

STEP 3

Substitute the given values for the slope and point into the formula.
$y -8 =6(x -6)$

STEP 4

Now we have the equation of the line in point-slope form.
$y -8 =6(x -6)$ This is the equation of the line with a slope of6 that passes through the point (6,8).

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